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Hoochie [10]
3 years ago
7

A bag contains 5 blue marbles, 2 black marbles, and 3 red marbles. A marble is randomly drawn from the bag. What is the probabil

ity of not drawing a black marble
Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0
80% Add up the marbles. 10 marbles. Divide the total amount of marbles by the number of blue and red marbles. That should equal 20%. That would be the probability of drawing a black marble. So, 80% is the answer
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Ten times the square of a non zero number is equal to eighty times the number
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5 0
3 years ago
Prove that √[(√3-√2)/(√3+√2)] = 0.318, where √3 = 1.732 and √2 = 1.414​
Vlada [557]
<h2><u>Explanation</u><u>:</u></h2>

{\large{\underline{\underline{\bf{\purple{Question \:  : - }}}}}}

{\underline{\underline{\sf{\red{Prove \:  That :-}}}}}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\dfrac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}} = 0.318}} \end{gathered}

\small{\underline{\underline{\sf{\red{Where  :-}}}}}

\bf{\green{\sqrt{3}}} = 1.732

\bf{\green{\sqrt{2}}} = 1.414

\begin{gathered}\end{gathered}

\large{\underline{\underline{\bf{\purple{Solution \: : - }}}}}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\dfrac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\red \divideontimes Here, we have provided that 3 = 1.732 and 2 = 1.414. So, we put the given values in equation.

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\dfrac{\sqrt{3} - \sqrt{2}}{\sqrt{3} + \sqrt{2}}} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\dfrac{1.732 - 1.414}{{1.732 + 1.414}}} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\dfrac{0.318}{3.146}} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{\sqrt{\cancel{\dfrac{0.318}{3.146}}} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{ \sqrt{0.101} = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\sf{0.318 = 0.318}} \end{gathered}

\begin{gathered}\end{gathered}

\begin{gathered}  \dashrightarrow{\underline{\underline{\sf{ \red{LHS = RHS }}}}} \end{gathered}

\begin{gathered}\end{gathered}

{\bigstar{\overline{\underline{\boxed{\textsf{\textbf{\green{Hence Proved !}}}}}}}}

3 0
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vodomira [7]
Sorry, is there more info so I can answer??
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Alik [6]
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4 0
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