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leva [86]
3 years ago
8

A steam power plant receives heat from a furnace at a rate of 300 GJ/h. Heat losses to the surrounding air from the steam as it

passes through the pipes and other components are estimated to be about 16 GJ/h. If the waste heat is transferred to the cooling water at a rate of 140 GJ/h, determine (a) net power output and (b) the thermal efficiency of this power plant.
Engineering
1 answer:
shutvik [7]3 years ago
7 0

Answer:

Net Power output  144 GJ/h

\eta = 51.41 %

Explanation:

Given data:

Heat received = 300 GJ/h

                        = \frac{300\times 10^9}{3600} J/s

                        = 77.78 \times 10^6 W

Heat lost Q_2 = 16 GJ/h

Heat to the water = Q_3 = 140 GJ/h

Net Power output = Q_1 - Q_2 -Q_3

                  = 300 - 16 - 140

                   = 144 GJ/h

                   =\frac{144\times 10^9}{3600} = 40\times 10^8 J/s

thermal efficiency

\eta = \frac{net\ power}{heat\ supplied}

= \frac{40\times 10^6}{ 77.78 \times 10^6}

       = 0.514 = 51.41 %

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Answer:

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Explanation:

#include<iostream>

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  struct linkedList *temp=head;

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      if(temp!= NULL)

      temp = temp->next;

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  int n,data;

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  head=insert(head,20);

  head=insert(head,5);

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