A. I believe, lmk if I’m right
Answer:
The resistance is 24.9 Ω
Explanation:
The resistivity is equal to:

The area is:
A = 60 * 60 = 3600 um² = 0.36x10⁻⁴cm²

If NA is greater, then, the term 1/NA can be neglected, thus the equation:

Where
V = 0.44 V
E = 11.68*8.85x10¹⁴ f/cm


The length is:
L = 10 - 0.335 = 9.665 um
The resistance is:

Answer:
the percent increase in the velocity of air is 25.65%
Explanation:
Hello!
The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.
m1=m2
Now remember that mass flow is given by the product of density, cross-sectional area and velocity
(α1)(V1)(A1)=(α2)(V2)(A2)
where
α=density
V=velocity
A=area
Now we can assume that the input and output areas are equal
(α1)(V1)=(α2)(V2)

Now we can use the equation that defines the percentage of increase, in this case for speed

Now we use the equation obtained in the previous step, and replace values

the percent increase in the velocity of air is 25.65%
The answer would be 23 because the engines in a horse is a amount of 9 engines in 69 cars