Technician is correct sorry if im wronghg
Solution :
Given :
The number of blows is given as :
0 - 6 inch = 4 blows
6 - 12 inch = 6 blows
12 - 18 inch = 6 blows
The vertical effective stress ![$=1500 \ lb/ft^2$](https://tex.z-dn.net/?f=%24%3D1500%20%5C%20lb%2Fft%5E2%24)
![$= 71.82 \ kN/m^2$](https://tex.z-dn.net/?f=%24%3D%2071.82%20%5C%20kN%2Fm%5E2%24)
![$ \sim 72 \ kN/m^2 $](https://tex.z-dn.net/?f=%24%20%5Csim%2072%20%5C%20kN%2Fm%5E2%20%24)
Now,
![$N_1=N_0 \left(\frac{350}{\bar{\sigma}+70} \right)$](https://tex.z-dn.net/?f=%24N_1%3DN_0%20%5Cleft%28%5Cfrac%7B350%7D%7B%5Cbar%7B%5Csigma%7D%2B70%7D%20%5Cright%29%24)
corrected N - value of overburden
effective stress at level of test
0 - 6 inch, ![$N_1=4 \left(\frac{350}{72+70} \right)$](https://tex.z-dn.net/?f=%24N_1%3D4%20%5Cleft%28%5Cfrac%7B350%7D%7B72%2B70%7D%20%5Cright%29%24)
= 9.86
6 - 12 inch, ![$N_1=6 \left(\frac{350}{72+70} \right) $](https://tex.z-dn.net/?f=%24N_1%3D6%20%5Cleft%28%5Cfrac%7B350%7D%7B72%2B70%7D%20%5Cright%29%20%24)
= 14.8
12 - 18 inch, ![$N_1=6 \left(\frac{350}{72+70} \right) $](https://tex.z-dn.net/?f=%24N_1%3D6%20%5Cleft%28%5Cfrac%7B350%7D%7B72%2B70%7D%20%5Cright%29%20%24)
= 14.8
![$N_{avg}=\frac{9.86+14.8+14.8}{3}$](https://tex.z-dn.net/?f=%24N_%7Bavg%7D%3D%5Cfrac%7B9.86%2B14.8%2B14.8%7D%7B3%7D%24)
= 13.14
= 13
Answer:
Ensure that all material and energy inputs and outputs are as inherently safe and benign as possible. Minimize the depletion of natural resources. Prevent waste. Develop and apply engineering solutions while being cognizant of local geography, aspirations, and cultures.Green engineering is the design, commercialization, and use of processes and products that minimize pollution, promote sustainability, and protect human health without sacrificing economic viability and efficiency.The goal of environmental engineering is to ensure that societal development and the use of water, land and air resources are sustainable. This goal is achieved by managing these resources so that environmental pollution and degradation is minimized.
Explanation:i helped
Answer:
That's a really nice question sadly I don't know the answer I'm replying to you cuz I'm tryna get points so... Sorry
Answer:
The distance measure from the wall = 36ft
Explanation:
Given Data:
w = 10
g =32.2ft/s²
x = 2
Using the principle of work and energy,
T₁ +∑U₁-₂ = T₂
0 + 1/2kx² -wh = 1/2 w/g V²
Substituting, we have
0 + 1/2 * 100 * 2² - (10 * 3) = 1/2 * (10/32.2)V²
170 = 0.15528V²
V² = 170/0.15528
V² = 1094.796
V = √1094.796
V = 33.09 ft/s
But tan ∅ = 3/4
∅ = tan⁻¹3/4
= 36.87°
From uniform acceleration,
S = S₀ + ut + 1/2gt²
It can be written as
S = S₀ + Vsin∅*t + 1/2gt²
Substituting, we have
0 = 3 + 33.09 * sin 36.87 * t -(1/2 * 32.2 *t²)
19.85t - 16.1t² + 3 = 0
16.1t² - 19.85t - 3 = 0
Solving it quadratically, we obtain t = 1.36s
The distance measure from the wall is given by the formula
d = VCos∅*t
Substituting, we have
d = 33.09 * cos 36. 87 * 1.36
d = 36ft