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4 years ago

Which statement(s) about galaxy groups is/are true?

Physics

1 answer:

AURORKA [14]4 years ago

3 0

Answer:

Option D and E are True.

Explanation:

Tidal streams can result from galaxies as a result of interaction between the galaxies due to the gravitational force. While the interaction is going on, stars and gas from the outer most part of the galaxies are usually cut off resulting in the formation of 2 tidal tails out of which one trails and the other one preceeds each galaxy.
The largest galaxies like our Milky way galaxies tend to have satellite or smaller galaxies which are bound due to gravitational force as a part of the sub group of larger galaxy which itself is a part of the Local group i.e., local galaxy cluster

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A block attached to a spring with an unknown spring constant oscillates with a period of 2.0 s. What is the period if

Zigmanuir [339]

Answer:

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

Explanation:

The statement is incomplete. We proceed to present the complete statement: A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if a. The mass is doubled? b. The mass is halved? c. The amplitude is doubled? d. The spring constant is doubled?

We have a block-spring system, whose angular frequency ( $\omega$ ) is defined by the following formula:

$\omega = \sqrt{\frac{k}{m} }$ (1)

Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

And the period ( $T$ ), measured in seconds, is determined by the following expression:

$T = \frac{2\pi}{\omega}$ (2)

By applying (1) in (2), we get the following formula:

$T = 2\pi\cdot \sqrt{\frac{m}{k} }$

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

8 0

3 years ago

What is the mass of 1.5 in newtons?

Thepotemich [5.8K]

Answer:

0.15 kg

Explanation:

F = mg

1.5N = m(9.8 m/s^2)

m = 0.15kg

8 0

3 years ago

A light microscope allows for more magnification than electron microscope because it uses a beam of visible light. true false

Igoryamba

False because light microscopes have low resolve and magnification.

4 0

3 years ago

At which point does the planet have the least gravitational force acting on it?

Elza [17]

Answer:

At which point does the planet have the least gravitational force acting on it?

Explanation:

In an elliptical orbit, when a planet is at its furthest point from the Sun, it is under the least amount of gravity, meaning that the force of gravity is strongest when it is closest.

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3 years ago

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During the summer months, why is the average temperature much higher in many regions of the globe?

GaryK [48]

C. More sunlight reaches the environment.

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