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Licemer1 [7]
3 years ago
12

I need help with this assignment please

Physics
1 answer:
tatiyna3 years ago
7 0

Answer:

ill try

Explanation:

let me find this answer for you

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A 25.0-kg child is standing at the edge of a horizontal merry-go-round with a radius of 2.40 m and a moment of inertia of 356 kg
motikmotik

Answer:

\omega_{f}=1.634\ rad/s  

Explanation:

given,  

diameter of merry - go - round = 2.40 m  

moment of inertia = I = 356 kg∙m²

speed of the merry- go-round = 1.80 rad/s

mass of child = 25 kg  

initial angular momentum of the system  

L_i = I\omega_i  

L_i =356\times 1.80  

L_i =640.8\ kg.m^2/s  

final angular momentum of the system  

L_f = (I_{disk}+mR^2)\omega_{f}  

L_f = (356 + 25\times 1.2^2)\omega_{f}  

L_f= (392)\omega_{f}  

from conservation of angular momentum  

L_i = L_f  

640.8= (392)\omega_{f}  

\omega_{f}=1.634\ rad/s  

8 0
3 years ago
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Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How hig
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Answer: Height should be 44.1 m.

Explanation:

Pressure exerted by stationary water stored at a height is,

P = ρgh

4.41 × 10^{5} = 1000× 10× h

solving we get,

h = 44.1 m

6 0
3 years ago
Review the following observations:
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Answer:

d.

Explanation:

no explanation

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3 years ago
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Which of the following is responsible for the formation of most of the worlds mountain ranges? a. epeirogenic changes
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I would think it would be A

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3 years ago
In an evaporation of water experiment, the initial mass of water in a beaker was 10.5775 +/- 0.0002 g. After some time, the mass
muminat

Answer:

Explanation:

The theory of  propagation of error in case of addition and subtraction states that maximum errors are added in absolute terms in both the operation of addition and subtraction . So in this case the subtracted value will be

10.5775 - 10.3005

= .2770 g

errors will be added ie in subtracted value we can find error to the tune of

.0002 + .0002 = .0004 g

So the subtracted value will be written as

.2770 ± .0004

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3 years ago
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