Question

A sample of air with a volume of 2.20m3 at a pressure of 105 KPa and a temperature of 30c is cooled to 10c and the pressure is reduced to 75.0 KPa.
What is the new volume?
6.9
1.34
2.56
43.0
2.88

Answer 1

It would be 43.0


hope it's right sir

Answer 2

Answer: The answer is 2.88 m3

Explanation: Since temperature, pressure and volume are given in the question, the general gas equation will be useful in calculating the new volume.

General gas equation,

(P1V1)/T1 = (P2V2) /T2 ................ (1)

Where,

P1 = Initial pressure

P2 = Final pressure

V1 = Initial volume

V2 = Final volume

T1 = Initial temperature in kelvin

T2 = Final temperature in Kelvin

Hence, from the question :

P1 = 105 KPa = 105,000 Pa

P2 = 75 KPa = 75,000 Pa

V1 = 2.20 m3

V2 =?

T1 = 30 °C = (273+30) K = 303 K

T2 =10 °C = (273+10) K = 283 K

Therefore, substitute these value into the general gas equation as given in eq (1) above.

V2 = (P1V1T2) /P2V1

V2 = (105000×2.2×283)/ (75000×303)

V2 = 2.88 m3