1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galina1969 [7]
3 years ago
12

A fan connected to a 120-volt electrical system by an extension cord was worn through and exposed the bare, energized conductor,

which made contact with the ladder. The ground wire was not attached to the male end of the cord's plug. When the energized conductor made contact with the ladder, the path to ground included the worker's body, resulting in death. What contributed to the electrocution?
Physics
2 answers:
kari74 [83]3 years ago
8 0

Answer: the ladder

Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.

iragen [17]3 years ago
8 0

Answer:

The worker completed the circuit.

Explanation:

Thinking process:

Electricity is the flow of electrons in a circuit. There is one condition for the electrons to flow - the completion of a circuit. In order for that to be established, there must be a side with low electron concentration or affinity for electrons.

The earth has an infinite affinity for electrons. Thus, earth wires are used to channel an excess amount of electrons there. This prevents the short circuiting injuring a person. Hence, a three-pin plug.

Because there was not insulation, like rubber, an alternative pathway could not be found for electrons. Hence the worker was electrocuted as the electric current passed through him.

You might be interested in
Determine the maximum theoretical speed that may be achieved over a distance of 66 m by a car starting from rest, knowing that t
My name is Ann [436]

Answer:

v=32.49 m/s

Explanation:

Given that

Distance ,d= 66 m

Initial speed of the car ,u = 0 m/s

Coefficient of friction ,μ = 0.8

Lets take the total mass of the car = m

The acceleration of the car is given as

a = μ g                               ( g= 10 m/s² )

Now by putting the values in the above equation we get

a= 0.8 x 10 m/s²

a= 8 m/s²

We know that ,final speed is given as

v²= u ²+ 2 a d

Now putting the value

v²=0² + 2 x 8 x 66

v²= 1056

v=32.49 m/s

3 0
3 years ago
You are coasting on your 12-kg bicycle at 13 m/s and a 5.0-g bug splatters on your helmet. The bug was initially moving at 1.5 m
Brut [27]

Answer:

a) Pi,c = 1066 kgm/s

b) Pi,b = 0.0075 kgm/s  

c) ΔV = - 0.0007 m/s

d) ΔV = - 0.0008 m/s

Explanation:

Given:-

- The mass of the bicycle, mc = 12 kg

- The mass of passenger, mp = 70 kg

- The mass of the bug, mb = 5.0 g

- The initial speed of the bicycle, vpi = 13 m/s

- The initial speed of the bug, vbi = 1.5 m/s

Find:-

a.What is the initial momentum of you plus your bicycle?

b.What is the initial momentum of the bug?

c.What is your change in velocity due to the collision the bug?

d.What would the change in velocity have been if the bug were traveling in the opposite direction?

Solution:-

- First we will set our one dimensional coordinate system, taking right to be positive in the direction of bicycle.

- The initial linear momentum (Pi,c) of the passenger and the bicycle would be:

                       Pi,c = vpi* ( mc + mp)

                       Pi,c = 13* ( 12+ 70 )

                       Pi,c = 1066 kgm/s  

- The initial linear momentum (Pi,b) of the bug would be:

                       Pi,b = vbi*mb

                       Pi,b = 0.005*1.5

                       Pi,b = 0.0075 kgm/s  

- We will consider the bicycle, the passenger and the bug as a system in isolation on which no external unbalanced forces are acting. This validates the use of linear conservation of momentum.

- The bicycle, passenger and bug all travel in the (+x) direction after the bug splatters on the helmet.

                       Pi = Pf

                       Pi,c + Pi,b = V*(mb + mc + mp)

Where,    V : The velocity of the (bicycle, passenger and bug) after collision.

                      1066 + 0.0075 = V*( 0.005 + 12 + 70 )

                      V = 1066.0075 / 82.005

                      V = 12.9993 m/s

- The change in velocity is Δv = 13 - 12.9993 =  - 0.00070 m/s      

- If the bug travels in the opposite direction then the sign of the initial momentum of the bug changes from (+) to (-).

- We will apply the linear conservation of momentum similarly.

                      Pi = Pf

                      Pi,c + Pi,b = V*(mb + mc + mp)        

                      1066 - 0.0075 = V*( 0.005 + 12 + 70 )

                      V = 1065.9925 / 82.005

                      V = 12.99911 m/s

- The change in velocity is Δv = 13 - 12.99911 =  -0.00088 m/s      

7 0
4 years ago
Read 2 more answers
Using the equation zeff=z−s and assuming that core electrons contribute 1.00 and valence electrons contribute 0.00 to the screen
DIA [1.3K]
Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help. 

<span>Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 17- 10 =7 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 19- 10 = 9 
</span>
S = 2 + 6.8 + 2.45 = 11.25 
<span>Zeff(Cl^-) = 17 – 11.25 = 5.75 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence </span>
<span>Zeff(K^+) = 19 - 11.25 = 7.75</span>
5 0
3 years ago
Read 2 more answers
What do we call the center of an atom that contains the mass of the<br> with<br> ca
Delvig [45]

Answer:

Hope this helps! Please Mark Brainliest!

Explanation:

The Nucleus: The Center of an Atom. The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels.

6 0
3 years ago
Which features on mars point to the possibility of liquid water on the planet?
Stells [14]
     In 2011 NASA researchers identified features on Mars known as Recuring Slope Lineae ( or RSL ). RSL are relatively dark and narrow features.They are thought to be a signs of salty liquid water on Mars. One hypothesis for RSL formation is that they form when underground bodies of salty water leak into the surface.
   Answer: Recuring Slope Lineae. 
7 0
3 years ago
Read 2 more answers
Other questions:
  • 10 kg of R-134a fill a 1.115-m^3 rigid container at an initial temperature of -30∘C. The container is then heated until the pres
    9·1 answer
  • The precision of a laboratory instrument is ± 0.05 g. The accepted value for your measurement is 7.92 g. Which measurements are
    13·1 answer
  • A cat is chasing a mouse across a 1.3 m tall dining table. The mouse darts to the side and the cat accidentally slides off, land
    9·1 answer
  • Calculate the density of an object with a volume of 18m3 and a mass of 3.5kg?
    5·1 answer
  • There are many forms of energy. All energy falls into one of two categories, either potential or kinetic energy. A Newton's Crad
    11·1 answer
  • What’s Chemical energy
    13·2 answers
  • A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300
    14·1 answer
  • Two gravitational forces act on a
    13·1 answer
  • How is the way that allows us to listen to an AM/FM Radio in our car is different from the wave that allows us to listen to mu
    13·1 answer
  • A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!