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galina1969 [7]
2 years ago
12

A fan connected to a 120-volt electrical system by an extension cord was worn through and exposed the bare, energized conductor,

which made contact with the ladder. The ground wire was not attached to the male end of the cord's plug. When the energized conductor made contact with the ladder, the path to ground included the worker's body, resulting in death. What contributed to the electrocution?
Physics
2 answers:
kari74 [83]2 years ago
8 0

Answer: the ladder

Explanation: since the energized conductor is already in contact with the ladder there by making electric current to flow. The base of the ladder is on the ground there by making the circuit to be complete and causing electrocution.

iragen [17]2 years ago
8 0

Answer:

The worker completed the circuit.

Explanation:

Thinking process:

Electricity is the flow of electrons in a circuit. There is one condition for the electrons to flow - the completion of a circuit. In order for that to be established, there must be a side with low electron concentration or affinity for electrons.

The earth has an infinite affinity for electrons. Thus, earth wires are used to channel an excess amount of electrons there. This prevents the short circuiting injuring a person. Hence, a three-pin plug.

Because there was not insulation, like rubber, an alternative pathway could not be found for electrons. Hence the worker was electrocuted as the electric current passed through him.

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The more ______ an object moves, the more __________ it has (Kinetic Energy)
belka [17]

Answer:

__________

Explanation:

3 0
3 years ago
What is the frequency of an ocean wave that is traveling at a speed of 45 m/s if it has a wavelength of 3 meters.
vaieri [72.5K]

Answer:

Frequency, f = 15 Hz      

Explanation:

We have,

Speed of an ocean wave is 45 m/s

Wavelength of a wave is 3 m

It is required to find the frequency of an ocean wave.

Speed of a wave, v=f\lambda, f = frequency of ocean wave

f=\dfrac{v}{\lambda}\\\\f=\dfrac{45}{3}\\\\f=15\ Hz

So, the frequency of an ocean wave is 15 Hz.

5 0
3 years ago
In an electric vehicle, each wheel is powered by its own motor. The vehicle weight is 4,000 lbs. By regenerative braking, its sp
Slav-nsk [51]

Answer:

the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

Explanation:

Given that;

weight of vehicle = 4000 lbs

we know that 1 kg = 2.20462

so

m = 4000 / 2.20462 =  1814.37 kg

Initial velocity V_{i} = 60 mph = 26.8224 m/s

Final velocity V_{f} = 30 mph = 13.4112 m/s

now we determine change in kinetic energy

Δk = \frac{1}{2}m(  V_{i}² - V_{f}² )

we substitute

Δk = \frac{1}{2}×1814.37( (26.8224)² - (13.4112)² )

Δk = \frac{1}{2} × 1814.37 × 539.5808

Δk = 489500 Joules

we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule

so

Δk = 489500 / 3.6 × 10⁶

Δk = 0.13597 ≈ 0.136 kWh

Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

4 0
3 years ago
In a pool game, the cue ball, which has an initial speed of 3.0 m/s, make an elastic collision with the eight ball, which is ini
zhenek [66]

Explanation:

Given

initial speed(u)=3 m/s

mass of each ball is m

Let the cue ball is moving in x direction initially

In elastic collision Energy and momentum is conserved

Let u be the initial velocity and v_1 , v_2 be the final velocity of 8 ball and cue ball respectively

\frac{mu^2}{2}+0=\frac{mv^2_1}{2}+\frac{mv^2_2}{2}

The angle after which cue ball is deflected is given by

\theta _1=90-40=50^{\circ}

Conserving momentum in x direction

mu=mv_1cos40+mv_2cos50

3=v_1cos40+v_2cos50

Along Y axis

0+0=v_1sin40-v_2sin50

v_1sin40=v_2sin50

substitute the value of v_1

we get v_2=1.912 m/s

v_1=2.27 m/s

5 0
3 years ago
A block of mass m moving with a velocity v collides with a mass 2m at rest. Consider the collision is elastic, we have to find t
lions [1.4K]

Answer:

vf_{1} =\frac{1}{3} v:Final block velocity (toward the left)

vf_{2} =\frac{2}{3} v :Final mass velocity (to the right)

Explanation:

To solve this problem we apply the theory of shocks:

In an elastic shock the kinetic energy and the amount of linear movement or momentum are conserved.

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1.

Principle of conservation of the momentum:

m1vi1+m2vi2=m1vf1+m2vf2 Equation 1

Formula to calculate the coefficient of elastic restitution (e):

e=\frac{vf_{2}-vf_{1}  }{vi_{1}-vi_{2}  } Equation 2

m1: Block mass

m2: mass of the  body that collides with the block

Vi1,vf1: initial, final velocity of the block

Vi2,vf2: initial, final velocity of the  body that collides with the block

Of the problem data we know that:

m1=m , m2 = 2m, vi1=v and vi2=0,  then, we replace this information in equation (1) :

mv+0=mvf1+2mvf2  we divide by m:

v=vf1+2vf2 Equation (3)

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1,then , we we replace this information in equation (2)

1=\frac{vf_{2}-vf_{1}  }{v-0}  

v=vf2-vf1 Equation (4)

vf2=v+vf1 Equation (5)

We replace the equation 5 in the equation (3)

v=vf1+2(v+vf1)

v=vf1+2v+2vf1

-3vf1=v

vf_{1} = -\frac{1}{3} v

We replace Vf1=(-1/3)v in the equation (5):

vf_{2} =v-\frac{1}{3} v

vf_{2} =\frac{2}{3} v

Answer;

vf_{1} =\frac{1}{3} v:Final block velocity (toward the left)

vf_{2} =\frac{2}{3} v :Final mass velocity (to the right)

5 0
2 years ago
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