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Reptile [31]
3 years ago
13

Which prediction is true based on this population pyramid?

Physics
2 answers:
Alika [10]3 years ago
7 0
The population is growing rapidly
Westkost [7]3 years ago
3 0
The population is growing rapidly
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¿Qué tiempo realiza un avión de la Cd. de México a Cancún, si la distancia entre ambos es de 1608.9Km y el avión viaja a una rap
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I can help you with that if you translate to English
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A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the
Liono4ka [1.6K]
The energy of the ski lift at the base is kinetic energy:
K= \frac{1}{2}mv^2
where m is the mass of the ski lift+the people carried, and v=15.5 m/s is velocity at the base.
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is 
U=mgh
where g=9.81 m/s^2 and h is the height at the top of the hill.

So, since the total energy must conserve, we have
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8 0
3 years ago
Which element is magnetic?<br> Answer<br> cobalt
Gnoma [55]

Which element is magnetic?

Answer

cobalt

4 0
3 years ago
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The relatively small, rocky bodies generally found orbiting between mars and jupiter are known as _____. meteoroids satellites c
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6 0
3 years ago
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Suppose the original segment of wire is stretched to 10 times its original length. How much charge must be added to the wire to
Debora [2.8K]

Here we want to study how the linear charge density changes as we change the measures of our body.

We will find that we need to add 9*Q of charge to keep the linear charge density unchanged.

<em>I will take two assumptions:</em>

The charge is homogeneous, so the density is constant all along the wire.

As we work with a linear charge density we work in one dimension, so the wire "has no radius"

Originally, the wire has a charge Q and a length L.

The linear charge density will be given by:

λ = Q/L

Now the length of the wire is stretched to 10 times the original length, so we have:

L' = 10*L

We want to find the value of Q' such that λ' (the <u>linear density of the stretched wire</u>) is still equal to λ.

Then we will have:

λ' = Q'/L' = Q'/(10*L) = λ = Q/L

Q'/(10*L) = Q/L

Q'/10 = Q

Q' = 10*Q

So the new <u>charge must be 10 times the original charge</u>, this means that we need to add 9*Q of charge to keep the linear charge density unchanged.

If you want to learn more, you can read:

brainly.com/question/14514975

6 0
2 years ago
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