The airplane is tracked for another 123° in the vertical eastwest plane
By definition, the refractive index is
n = c/v
where c = 3 x 10⁸ m/s, the speed of light in vacuum
v = the speed of light in the medium (the liquid).
The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz
Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m,
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s
The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406
Answer: a. 1.14
The correct answer is B a magnetic field
π=iMRT
Where, π is Osmotic pressure,
i=1 for non-electrolytes,
M is molar concentration of dissolved species (units of mol/L)
R is the ideal gas constant = 0.08206 L atm mol⁻¹K⁻¹,
T is the temperature in Kelvin(K),
Here, to calculate M convert into standard units mg tog, ml to L, c to Kelvin
M= (
*10⁻³ )/ 0.175 =(5.987 *10⁻⁵)mol / 0.175L = 34.21*10⁻⁵ mol/L
π=iMRT=(1)*(34.21*10⁻⁵)*(0.08206)*(298.15)=837×10⁻⁵= 8.37×10⁻³ atm
=6.36 torr
(1 atm=760 torr, 1 Kelvin =273.15 °C, 1L=1000ml, 1g=1000mg)
Answer:
959183.7 kg
Explanation:
from the question we have :
young modulus = 5 x 10^{9} N/m^{2}
strain = 2% = 2÷100 = 0.02
diameter = 0.03 m
radius = 0.015 m
acceleration due to gravity (g) = 9.8 m/s^{2}
we can get the mass from the formula below
young modulus = stress ÷ strain
where
stress = \frac[force}{area} = \frac {mass x g}{area}
area = 2πr = 2π x 0.015 = 0.094
therefore
young modulus = \frac{\frac {mass x g}{area}}{strain}
5 x 10^{9} = \frac{\frac {mass x 9.8}{0.094}}{0.02}
mass = \frac{5 x 10^{9} x 0.02 x 0.094}{9.8}
mass = 959183.7 kg
