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tamaranim1 [39]

3 years ago

6

A scientific theory?

1 answer:

Sonbull [250]3 years ago

8 0

<span>A scientific theory is a specific type of theory that is used in the scientific method. The theories are not guesses they are reliable sources of the real world.</span>

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A straight wire is aligned east-west in a region where Earth’s magnetic field has magnitude 0.0780 mT and direction 67.1° below

Sergio [31]

Explanation:

It is given that,

Earth's magnetic field, $B=0.078\ mT=0.078\times 10^{-3}\ T$

Direction of magnetic field, 67.1 degrees below the horizontal, with the horizontal component directed due north.

The magnetic force on the wire per unit length of wire, $\dfrac{F}{L}=0.0300\ N/m$

(a) The given scenario is shown in the attached figure as :

Using the right hand rule to find the direction of magnetic force on the wire. By using this rule, we get the magnetic force acting on the wire is in upward direction.

(b) Let I is the current flowing in the wire. The magnetic force is given by the following formula as:

$F=ILB$

$I=\dfrac{F}{LB}$

$I=\dfrac{0.0300}{0.078\times 10^{-3}}$

I = 384.61 A

Hence, this is the required solution.

7 0

3 years ago

When a lift is at the highest level it has the most ?

Olegator [25]

Answer:

kinetic energy

Explanation:

that I think

6 0

3 years ago

Read 2 more answers

Consider the specific example of a positive charge q moving in the +x direction with the local magnetic field in the +y directio

Leto [7]

Answer:

Therefore the direction is in the <u>positive direction of the z axes</u>.

Explanation:

Let's recall that the magnetic force is given by:

$F_{B}=q(\vec{v} \times \vec{B})$

The unit vector of V is $\hat{i}$ and the unit vector of B is $\hat{j}$

So, the direction of the force will be defined as the cross product of i and j, and using the right hand rule:

$\hat{i} \times \hat{j} = \hat{z}$

Therefore the direction of the magnetic force is in the <u>positive direction of the z axes</u>.

I hope it helps you!

4 0

4 years ago

Read 2 more answers

A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h

Helen [10]

The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

Calculated value = 4.15 g/cm
accepted value = 8.64 g/cm

Substitute these values into equation 1

Error(%) = (4.15-8.64)100/8.64
Error(%) = -4.49(100)/8.64
Error(%) = -449/8.64
Error(%) = -51.97 %

Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

8 0

3 years ago

Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius

olasank [31]

Answer:

v₂ = 5131.42 m/s

Explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ = 84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

$v = \sqrt{\dfrac{GM}{r}}$

so,

$v \alpha \dfrac{1}{\sqrt{r}}$

now,

$\dfrac{v_1}{v_2} =\sqrt{\dfrac{r_2}{r_1}}$

$\dfrac{v_2}{4800} =\sqrt{\dfrac{8\times 10^7}{7 \times 10^7}}$

v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s

7 0

3 years ago