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Pachacha [2.7K]
3 years ago
15

The acceleration from gravity on the moon is 1.6 m/s. How much less force

Physics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

We use the relationship F = m x a, adapted for Weight: W = m x g

Weight is the force, m is the mass and g is the acceleration of gravity. Take an example: you are 100 kg made up of 70 kg of body mass and 30 kg of space suit. Your weight on the Moon would be 100 kg x 1.62 m/s^2 = 162 Newtons (weight force).

On Earth that would be a Weight of 100 kg x 9.81 m/s^2 = 981 Newtons.

Explanation:

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marshall27 [118]

Answer:

The Graph Shows World Disasters.

Answer Pt.2:

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3 0
2 years ago
Read 2 more answers
At a sports car rally, a car starting from rest accelerates uniformly at a rate of 5 m/s/s over a straight-line distance of 291
Bogdan [553]

Answer:

10.8 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Acceleration (a) = 5 m/s/s

Distance travelled (s) = 291 m

Time (t) taken =?

We can calculate the time taken for the car to cover the distance as follow:

s = ut + ½at²

291 = 0 × t + ½ × 5 × t²

291 = 0 + 2.5 × t²

291 = 2.5 × t²

Divide both side by 2.5

t² = 291 / 2.5

t² = 116.4

Take the square root of both side

t = √116.4

t = 10.8 s

Thus, it will take the car 10.8 s to cover the distance.

8 0
3 years ago
the goat weighs 900 N and is 1 meter from the fulcrum. The strongman pulls down on the lever 3 meters from the fulcrum. What is
garik1379 [7]

Answer: The smallest effort = 300N

Explanation:

Using one of the condition for the attainment of equilibrium:

Clockwise moment = anticlockwise moments

900 × 1 = 3 × M

Where M = the weight of the strong man

3M = 900

M = 900/3 = 300N

Therefore, 300N is the smallest effort that the strongman can use to lift the goat

6 0
3 years ago
The steps below describe how you hear. number the steps in the correct order. the first one is done for you
NNADVOKAT [17]

3

1

2

4

6

5

7

Hope this helps! : )

6 0
3 years ago
Using a simple pendulum, we can measure. (a) Acceleration along a circle (b) Acceleration due to gravity (c) Frequency (d) None
zalisa [80]

Answer:

Option B is the correct answer.

Explanation:

Period of simple pendulum is given by the expression T=2\pi \sqrt{\frac{l}{g}}, where l is the length of pendulum and g is the acceleration due to gravity value.

So if we have a simple pendulum with length l we can find its period. Using the above formula we can calculate  acceleration due to gravity value of that place.

So using simple pendulum we can measure acceleration due to gravity value.

Option B is the correct answer.

3 0
3 years ago
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