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Pachacha [2.7K]
3 years ago
15

The acceleration from gravity on the moon is 1.6 m/s. How much less force

Physics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

We use the relationship F = m x a, adapted for Weight: W = m x g

Weight is the force, m is the mass and g is the acceleration of gravity. Take an example: you are 100 kg made up of 70 kg of body mass and 30 kg of space suit. Your weight on the Moon would be 100 kg x 1.62 m/s^2 = 162 Newtons (weight force).

On Earth that would be a Weight of 100 kg x 9.81 m/s^2 = 981 Newtons.

Explanation:

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I need help in this pls i really need a answer
IrinaK [193]

Answer:

In terms of distance, average speed is 20 km/h

In terms of displacement, average speed is 0 km/h.

Explanation:

Total distance:

= (40.0 - 10.0) + (20.0 - 10.0) + (40.0 - 20.0) \\  = 30.0 + 10.0 + 20.0 \\  = 60.0 \: km

Total time is 3.0 hours

but:

average \: speed =  \frac{total \: distance}{total \: time}  \\

In terms of distance.

substitute:

average \: speed =  \frac{60.0}{3.0}  \\  \\  = 20 \:  {kmh}^{ - 1}

displacement = ( - 30.0) + 10 .0+ 20.0 \\  = 0

In terms of displacement:

speed =  \frac{0}{3}  \\  \\  = 0 \:  {kmh}^{ - 1}

3 0
3 years ago
Which statement about dwarf planets is true?
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5 0
3 years ago
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In which labeled portion of the curve would you use the heat of vaporization to calculate the heat absorbed? (image attached ins
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3 0
3 years ago
A stone is thrown vertically upwards with an initial velocity of 20m/sec. Find the maximum height ot reaches and the time taken
MAXImum [283]

Answer:

The height reached is 20m, The time taken to reach 20m is 2 seconds

Explanation:

Observing the equations of motion we can see that the following equation will be most helpful for this question.

v^{2} = u^{2} + 2as

We are given initial velocity, u

We know that the stone will stop at its maximum height, so final velocity, v

Acceleration, a

And we are looking for the displacement (height reached), s

Substitute the values we are given into the equation

0^{2} = 20^{2} + 2(10)s

Rearrange for s

0^{2} -20^{2} =20s

-400=20s

\frac{-400}{20} =s

s = -20 (The negative is just showing direction, it can be ignored for now)

The height reached is 20m

Use a different equation to find the time taken

s = vt - \frac{1}{2} at^{2}

Substitute in the values we have

-20=(0)t - \frac{1}{2} (10)t^{2}

Rearrange for t

-20 =0 -5 t^{2}

\frac{-20}{-5} =t^{2}

4 = t^{2}

t = 2s

The time taken to reach 20m is 2 seconds

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3 years ago
Fill in blank without a word bank (unit is wave nature of light) 1. As water waves travels through a slit barrier, they bend and
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1 diffraction 
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