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Pachacha [2.7K]
3 years ago
15

The acceleration from gravity on the moon is 1.6 m/s. How much less force

Physics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

We use the relationship F = m x a, adapted for Weight: W = m x g

Weight is the force, m is the mass and g is the acceleration of gravity. Take an example: you are 100 kg made up of 70 kg of body mass and 30 kg of space suit. Your weight on the Moon would be 100 kg x 1.62 m/s^2 = 162 Newtons (weight force).

On Earth that would be a Weight of 100 kg x 9.81 m/s^2 = 981 Newtons.

Explanation:

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Which of the following statements are true? Positively charged objects attract other positively charged objects. Negatively char
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Astronomers discover an exoplanet, a planet obriting a star other than the Sun, that has an orbital period of 3.27 Earth years i
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  r = 3.787 10¹¹ m

Explanation:

We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration

    F = ma

    G m M / r² = m a

The centripetal acceleration is given by

    a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

    v = d / t

The distance traveled Esla orbits, in a circle the distance is

    d = 2 π r

Time in time to complete the orbit, called period

     v = 2π r / T

Let's replace

    G m M / r² = m a

    G M / r² = (2π r / T)² / r

    G M / r² = 4π² r / T²

    G M T² = 4π² r3

     r = ∛ (G M T² / 4π²)

Let's reduce the magnitudes to the SI system

     T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)

     T = 1.03 10⁸ s

Let's calculate

      r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]

      r = ∛ (21.44 10³⁵ / 39.478)

      r = ∛(0.0543087 10 36)

      r = 0.3787 10¹² m

      r = 3.787 10¹¹ m

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