2 years ago

PLEASE HELP

Physics

1 answer:

blagie [28]2 years ago

8 0

Assuming Adam is on earth g= 9.8 m/s and m= weight/ gravity = 667/9.8 = 68 kg

You might be interested in

Plz help brainliest<br> plzzzzzzzzzzzzzzzzz!!!!!!!!!!!!!!

Likurg_2 [28]

Answer:

Explanation:

8 0

2 years ago

Sequence the steps used to extract metal from the earths core

Iteru [2.4K]

Methods of extraction include: extract by electrolysis, extract by reaction with carbon or carbon monoxide, and extracted by various chemical reactions. 《I hope tis help you》

4 0

2 years ago

Females are the only gender capable of suffering from an eating disorder.<br> A. true<br> B. false

AnnZ [28]

ANSWER
That’s false!!

8 0

2 years ago

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.0 m/s at ground level.

BARSIC [14]

Answer:

There is an interval of 24.28s in which the rocket is above the ground.

Explanation:

$y_{i}=0m$

$v_i=80\frac{m}{s}$

$a=4\frac{m}{s^2}$

$y_{e}=1000m$

$g=9.8\frac{m}{s^2}$

From Kinematics, the position $y$ as a function of time when the engine still works will be:

$y(t)=v_it+\frac{1}{2}at^2$

At what time the altitud will be $y_{e}=1000m$ ?

$v_it+\frac{1}{2}at^2=y_{e}$ ⇒ $\frac{1}{2}at^2+v_it-y_{e}=0$

Using the quadratic formula: $t_1=10s$ .

How much time does it take for the rocket to touch the ground? No the function of position is:

$y(t)=y_{e}+v_et-\frac{1}{2}gt^2$

Where our new initial position is $y_{max}$ , the velocity when the engine breaks is $v_e=v_i+at=120\frac{m}{s}$ and the only acceleration comes from gravity (which points down).