Answer:
the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions = 49.73 J/K.
Explanation:
3Fe2O3(s) + H2(g)-----------2Fe3O4(s) + H2O(g)
∆S°rxn = n x sum of ∆S° products - n x sum of ∆S° reactants
∆S°rxn = [2x∆S°Fe3O4(s) + ∆S°H2O(g)] - [3x∆S°Fe2O3(s) + ∆S°H2(g)]
∆S°rxn = [(2x146.44)+(188.72)] - [(3x87.40)+(130.59)] J/K
∆S°rxn = (481.6 - 392.79) J/K =88.81J/K.
For 3 moles of Fe2O3 react, ∆S° =88.81 J/K,
then for 1.68 moles Fe2O3 react, ∆S° = (1.68 mol x 88.81 J/K)/(3 mol) = 49.73 J/K the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions.
Answer;
The answer is No,
Explanation;
-The intersection of two parallel half-planes A and B is either a half-plane (either A or B, when A and B have similar orientation) or the empty set (when A and B have opposite orientation).
-When A and B are not parallel, their intersection is a maximal open region bounded by the two lines that define A and B, respectively. In this case, the intersection always exists and it is never a half-plane.
To increase the acceleration of the dog sled, increase the applied force on the sled and reduce the mass on the sled.
According to Newton's second law of motion, the force applied to an object is directly proportional to product of mass and acceleration of the object.
F = ma
where;
<em>a </em><em>is the </em><em>acceleration </em><em>of the dog sled</em>
To increase the acceleration of the dog sled:
- Increase the applied force on the sled.
- Reduce the mass on the sled.
Learn more about Newton's second law here: brainly.com/question/3999427
Answer:
The question is incomplete.
Answer: The answer is B The kinetic energy breaks the bonds between atoms.
Explanation:
