Answer:
α = 5.75°
Explanation:
In this case, the problem states that both springs have identical lenghts and we also have theri constant. We want to know the angle of the rod with the horizontal. This can be found with the following expression:
sinα = Δx/L
α = sin⁻¹ (Δx/L) (1)
However, we do not have Δx. This can be found when half of the weight of the rod is balanced. In this way:
F₁ = k₁*x₁ ----> x₁ = F₁ / k₁ (2)
And the force is the weight in half so: F₁ = mg/2
Replacing in (2) we have:
x₁ = (1.3 * 9.8) / (2 * 58) = 0.1098 m
Doing the same thing with the other spring, we have:
x₂ = (1.3 * 9.8) / (2 * 36) = 0.1769 m
Now the difference will be Δx:
Δx = 0.1769 - 0.1098 = 0.0671 m
Finally, we can calculate the angle α, from (1):
α = sin⁻¹(0.0671 / 0.67)
<h2>
α = 5.75 °</h2>
Hope this helps
Answer:
The units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
Explanation:
P² = a³ is the simplified version of Kepler's third law which governs the orbital motion of large bodies that orbit around a star. The orbit of each planet is an ellipse with the star at the focal point.
Therefore, if you square the year of each planet and divide it by the distance that it is from the star, you will get the same number for all the other planets.
Thus, the units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
Answer:
Explanation:
the one thrown below the horizontal is going straight down, while the one above the horizontal will experience a projectile motion which will makes it move farther away from the building where it was projected.
Answer:
a scientist will repeat his experiments to verify the results