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emmasim [6.3K]
4 years ago
9

A major difference between AC and DC electricity is that A) the current in AC electricity varies in magnitude and direction. B)

the current in DC electricity varies in magnitude and direction. C) the voltage in AC electricity varies in magnitude and direction. D) the voltage in DC electricity varies in magnitude and direction.
Physics
2 answers:
galina1969 [7]4 years ago
7 0

Answer:

A) the current in AC electricity varies in magnitude and direction.

C) the voltage in AC electricity varies in magnitude and direction.

Explanation:

In DC current and voltage the direction of current will not change with time and it always remains the same.

So here in DC voltage and DC current the magnitude may change with time but the direction will always remain same

While in AC voltage and AC current the direction of AC will change with time

periodically.

So here magnitude and direction both will change in AC current and AC voltage.

so the correct answer is

A)     the current in AC electricity varies in magnitude and direction.

C) the voltage in AC electricity varies in magnitude and direction.

Katen [24]4 years ago
3 0

Answer:

option  <u>A</u>    

Explanation:

AC stands for Alternating current and DC stands for Direct current. The main difference between AC and DC is that current changes direction in AC and not in DC. Actually the direction of flow of electrons reverses periodically. In direct current, the electrons flow in same direction.

Thus, option A is correct.

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A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00
Oxana [17]

Answer:

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

A_x = 0\\A_y = +2.00 km

- Displacement 2: 60.0° south of east for 7.00 km

So

B_x=(7.00)(cos (-45^{\circ}))=4.95 km\\B_y = (7.00)(sin (-45^{\circ}))=-4.95 km

- Displacement 3: 9.50 km 35.0° north of east

So

C_x=(9.50)(cos 35^{\circ})=7.78 km\\C_y=(9.50)(sin 35^{\circ})=5.45 km

So the net displacement along the two directions is:

R_x=A_x+B_x+C_x=0+4.95+7.78=12.73 km\\R_y=A_y+B_y+C_y=2.00+(-4.95)+5.45=2.50 km

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

R=\sqrt{R_x^2+R_y^2}=\sqrt{12.73^2+2.50^2}=12.97 km

7 0
3 years ago
A boat sends an ultrasound signal of frequency 30 kHz, and receives the signal after 6 s. If the speed of sound in water is 1500
natka813 [3]

Answer:

4500

Explanation:

hey there!

first we convert the khz to hz=30000hz

we use the formula 2d=distance×time

2d=1500×6

d=9000/2=4500

i think this is the right answer....

hope this helps u :)

3 0
3 years ago
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