All categories

4 years ago

What is the net work done on the 20kg block while it moves the 4 meters?

Physics

1 answer:

Vinil7 [7]4 years ago

5 0

Answer:

The answer to your question is 784.8 J. None of your answer, did you forget some information?

Explanation:

Data

mass = 20 kg

distance = 4 m

work = ?

Formula

Work = force x distance

Force = mass x gravity

Process

1.- Calculate the weight of the block

Weight = 20 x 9.81

Weight = 196.2 N

2.- Calculate the work done

Work = 196.2 x 4

Work = 784.8 J

You might be interested in

Question 3 of 10

Volgvan

Answer:

This oxygen reacts with the carbon of the positive electrodes, forming carbon dioxide, so they gradually burn away. As a result, the positive electrodes have to be replaced frequently. This adds to the cost of the process.

5 0

3 years ago

Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

6 0

3 years ago

9. A van travels at a speed of 40.0 m/s has a mass of 600kg. What is the van’s kinetic energy? *

Zina [86]

$ke = \frac{1}{2} m{v}^{2} \\ = \frac{1}{2} (600)( {40}^{2} ) \\ = 300 \times 800 = 240000 = 240kjoule$

8 0

3 years ago

A baseball with a mass of 0.8 kg is given an acceleration of 20m/s.how much force was applied to the ball

Delicious77 [7]

F=mass x acceleration = ma= 0.8*20 = 16N

5 0

3 years ago

Complete the sentence to explain when waves interact.

rewona [7]

Answer:

Objects and waves

Explanation:

7 0

3 years ago