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gulaghasi [49]
3 years ago
10

What is the net work done on the 20kg block while it moves the 4 meters?

Physics
1 answer:
Vinil7 [7]3 years ago
5 0

Answer:

The answer to your question is 784.8 J. None of your answer, did you forget some information?

Explanation:

Data

mass = 20 kg

distance = 4 m

work = ?

Formula

Work = force x distance

Force = mass x gravity

Process

1.- Calculate the weight of the block

     Weight = 20 x 9.81

     Weight = 196.2 N

2.- Calculate the work done

     Work = 196.2 x 4

     Work = 784.8 J

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How is force proportional to mass?
sukhopar [10]

Answer:

a = F / m

Explanation:

force same -> mass variable

more mass -> less force

8 0
3 years ago
How does the thickness of the lens affects its focal length plz ans this i will mark as brainliest
Oksanka [162]

Hello! :)

The focal length of the lens tells you how far away from the lens a focused image is created, if light rays approaching the lens are parallel. A lens with more “bending power” has a shorter focal length, because it alters the path of the light rays more effectively than a weaker lens. Most of the time, you can treat a lens as being thin and ignore any effects from the thickness, because the thickness of the lens is much less than the focal length. But for thicker lenses, how thick they are does make a difference, and in general, results in a shorter focal length.

Hope I helped and didn’t answer too late!

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5 0
3 years ago
A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0
3 years ago
A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force A, as part
aniked [119]

Answer:

The ratio is 1:1

Explanation:

Firstly we are told the in (a) we have a force which A given to be: FA

We are then told the are two other forces which a B and C which are equal.

These forces are given to be F and 19.5° away from A.

We are then told that the force on the elephant is now three times, of what it was when we only had force A.

Since we are told that B and C are eqaula.

If we say FA = 2N

Then in order for it to be three times, we would have to add 4N since it was the only force present at the time.

If we add two equal forces, then we can devide that 4 by 2.

We then find out that F =2N

and thus equal to FA.

Therefore the ratio of F/FA is

!:1

4 0
3 years ago
What speed should a satellite with a mass of 1500 kg at 8,500 km above the center of the earth be traveling at in order to stay
hodyreva [135]

Answer:

6844.5 m/s.

Explanation:

To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.

Formula for centripetal force is;

F_c = mv²/r

Formula for gravitational force is:

F_g = GmM/r²

Thus;

mv²/r = GmM/r²

m is the mass of the satellite and M is mass of the earth.

Making v the subject, we have;

v = √(GM/r)

We are given;

G = 6.67 × 10^(-11) m/kg²

M = 5.97 × 10^(24) kg

r = 8500 km = 8500000

Thus;

v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.

7 0
3 years ago
Read 2 more answers
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