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drek231 [11]
3 years ago
10

If an atom has 6 protons and 7 neutrons it will have 7 electrons if it is a neutral atom.

Chemistry
2 answers:
oksian1 [2.3K]3 years ago
7 0

Answer:

<u>NO</u>

Explanation:

To maintain electric neutrality, the atom has to have equal number of electrons and protons. Therefore, it needs to have 6 electrons to be neutral.

REY [17]3 years ago
4 0
Your answer is no hope it helped
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Cosmic rays are
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A. High energy radiation produced in the ozone layer. (:

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2 years ago
What is the mass of 1.45 moles of silver sulfate?
tatuchka [14]

Answer:

449.5 g

Explanation:

Silver sulfate- Ag2SO4

M(Ag)=107 g/mol => M(Ag2)=214 g/mol

M(S)=32 g/mol

M(O)=16 g/mol => M(O4)=64 g/mol

M(Ag2SO4)=310 g/mol

n=1.45 mol

m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g

3 0
2 years ago
Read 2 more answers
Hiw many tons of sulfur are consumed in the production of 98 tons of sulfuric acid?
MariettaO [177]
Well as far as I know to make one ton of sulfuric acid takes 1,000,000 grams, so the answer should be 98,000,000 grams
5 0
3 years ago
The combined gas law does not account for changes in
True [87]

Answer:

Power

Explanation:

The combined gas law is...

P1V1/T1 = P2V2/T2

These variables stand for pressure, volume, and temperature.

- Hope this helps! If you need a further explanation please let me know.

5 0
3 years ago
The reaction of 4.8g of sulfur and 5.4g aluminum yields 4.5g Al2S3. 3S+2AL--&gt;Al2S3 Determine the percent yield of Al2S3.
Goshia [24]

Answer:

59.9% is the percent yield for the 4.5 g of produced Al₂S₃

Explanation:

Let's determine the reaction:

3S  +  2Al  →  Al₂S₃

First of all, let's determine the limiting reactant. We need to convert the mass to moles:

4.8 g /32.06g/mol = 0.150 moles of S

5.4 g / 26.98 g/mol = 0.200 moles of Al

3 moles of S react to 2 moles of Al

Then, 0.150 moles of S may react to (0.150 . 2)/3 = 0.1 ,moles of Al

We have 0.200 moles and we only have 0.1. As we have excess of Al, this is the excess reactant. In conclussion, the limiting reagent is S.

2 moles of Al react to 3 moles of S

Then 0.2 moles of Al may react to (0.2 . 3) /2 = 0.3 moles of S. (We only have 0.150 moles)

Let's go to the product, 3 moles of S can produce 1 mol of Al₂S₃

Then 0.150 moles of S, may produce (0.150 . 1) /3 = 0.05 moles.

We convert moles to mass to determine the thoretical yield:

0.05 mol . 150.15g /mol =  7.50g

Percent yield = (Produced yield/Theoretical yield) . 100

% = (4.5g / 7.5g) . 100 = 59.9%

8 0
2 years ago
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