At a constant speed of 5.00 m/s, the speed at which the poodle completes a full revolution is
so that its period is 
(where 1 revolution corresponds exactly to 360 degrees). We use this to determine how much of the circular path the poodle traverses in each given time interval with duration 
. Denote by 
the angle between the velocity vectors (same as the angle subtended by the arc the poodle traverses), then
We can then compute the magnitude of the velocity vector differences 
for each time interval by using the law of cosines:
and in turn we find the magnitude of the average acceleration vectors to be
So that takes care of parts A, C, and E. Unfortunately, without knowing the poodle's starting position, it's impossible to tell precisely in what directions each average acceleration vector points.
The formula written in the 3rd line above the picture is WRONG. Don't use it. Use the formula the way it's printed in the picture.
V = d / t
That means Speed = (distance) / (time)
The question tells us that v = 330 m/s
So you write 330 m/s in the equation in place of 'v', like this:
330 m/s = (distance) / (time)
The question also tells us that the time is 0.4 second
So you write 0.4 sec in place of 'time', like this:
330 m/s = (distance) / (0.4 second)
Finally, you take this, and multiply each side of the equation by (0.4 sec). Then it'll say
distance = (330 m/s) x (0.4 second)
As soon as you do that one single multiplication there with your pencil or your calculator, you'll have the distance.
This is either the 2nd or 3rd time you've posted this same exact question since last weekend. It can be solved THIS time exactly like the answers that were posted those other times.
The DOT in the picture is marked for the wrong choice. Use the formula that's printed in the picture, not copied above it.
Answer:
11.) g = 3.695 m/s^2
12.) g = 8.879 m/s^2
13.) E = 8127 N/C
Explanation:
11.) Given that the
Mercury mass M = 3.3 × 10^23kg
Radius r = 2.44 ×10^6 m
Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2
Gravitational field strength g can be calculated by using the formula below
g = GM/r^2
Substitutes all the parameters into the formula
g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2
g = 2.2×10^13/5.954×10^12
g = 3.695 m/s^2
12.) Given that the
Venus mass M = 4.87×10^24kg
Radius r = 6.05 × 10^6 m
Using the same formula for gravitational field strength g
g = GM/R2
Substitute all the parameters into the formula
g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2
g = 3.25×10^14/3.66×10^13
g = 8.879 m/s^2
13.) Given that the
Charge = 2.26 nC = 2.26×10^-9
Distance d = 0.05m
Electric field strength E can be calculated by using the formula below
E = Kq/d^2
Where
K = electrostatic constant 8.99 × 10^9 Nm2/C2
Substitutes all the parameters into the formula
E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2
E = 20.3174/2.5×10^-3
E = 8126.96 N/C
Answer:
They both are part of electromagnetic radiation.
Radio waves have longer wavelength than visible waves.
Radio waves have lower frequency than visible waves.
Explanation:
