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4 years ago

A body oscillates with 25hz what is its time period

Physics

1 answer:

Semmy [17]4 years ago

4 0

Answer:

4 seconds

Explanation:

The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).

The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).

A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.

The period (T) is given as:

$Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds$

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Answer:

$Q = 4.40 \times 10^5 Cal$

Explanation:

Here we know that initial temperature of ice is given as

$T = 0^o C$

now the latent heat of ice is given as

$L = 80 Cal/g$

now we also know that the mass of ice is

$m = 5.50 kg$

so here we know that heat required to change the phase of the ice is given as

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$Q = (5.50 \times 10^3)(80)$

$Q = 4.40 \times 10^5 Cal$

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4 years ago

After t hours a freight train is s(t) = 18t2 − 2t3 miles due north of its starting point (for 0 ≤ t ≤ 9). (a) Find its velocity

BartSMP [9]

Answer:

Explanation:

Given the equation modelled by the height of the train given as:

s(t) = 18t²-2t³ for for 0 ≤ t ≤ 9

a) Velocity is the rate of change of displacement.

Velocity = dS(t)/dt

V = dS(t)/dt = 36t - 6t² miles

Velocity at t = 3hrs is determiner by substituting t = 3 into the velocity function.

V = 36(3) -6(3)²

V= 108 - 72

Velocity = 36mi/hr

b) for Velocity at time = 7hrs

V(7) = 36(7) - 6(7)²

V(7) = 252 - 294

V(7) = -42mi/hr

The velocity at t = 7hrs is -42mi/hr

c) Acceleration is the rate of change of velocity.

a(t) = dV(t)/dt

Given v(t) = 36t - 6t²

a(t) = 36 - 12t

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3 years ago

A kid is on a stationary sled, on

gregori [183]

The mass of the kid and the sled is 50.0 kg

Explanation:

The sled starts to move when the force applied becomes larger than the maximum force of static friction, which is given by

$F_{max} = \mu_s mg$

where

$\mu_s$ is the coefficient of static friction

m is the mass of the kid + the sled

$g=9.8 m/s^2$ is the acceleration of gravity

Here the sled starts moving when the force applied is 61.2 N, so

$F_{max}=61.2 N$

And we also know

$\mu_s = 0.125$

Therefore, we can find the mass of the kid and the sled by re-arranging the equation:

$m=\frac{F_{max}}{\mu_s g}=\frac{61.2}{(0.125)(9.8)}=50.0 kg$

Learn more about friction:

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4 years ago

Has a definite shape and definite volume. Question 4 options: liquid gas solid

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Answer:

solid

Explanation:

solid

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3 years ago

Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear

Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

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The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0

3 years ago