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iren [92.7K]
3 years ago
9

A body oscillates with 25hz what is its time period

Physics
1 answer:
Semmy [17]3 years ago
4 0

Answer:

4 seconds

Explanation:

The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).

The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).

A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.

The period (T) is given as:

Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds

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Answer:

The correct answer would be 200m

Explanation:

20x10=200

the previous answer is incorect from the other user.

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3 years ago
A block weighing 10 newtons is resting on a plane inclined 30° to the horizontal. What is the magnitude of the normal force acti
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Magnitude of normal force acting on the block is 7 N

Explanation:

10N = 1.02kg

Mass of the block = m = 1.02 kg

Angle of incline Θ =  30°

Normal force acting on the block = N

From the free body diagram,

N = mgCos Θ

N = (1.02)(9.81)Cos(30)

N = 8.66 N

Rounding off to nearest whole number,

N = 7 N

Magnitude of normal force acting on the block = 7 N

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2 years ago
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc
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when a circular plate of metal is heated in an oven, its radius increases at .03 cm/min, at what rate is the area increasing whe
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Answer:

Rate of change of area will be 9.796cm^2/min

Explanation:

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Radius of the circular plate r = 52 cm

Area is given by A=\pi r^2

So \frac{dA}{dt}=2\pi r\frac{dr}{dt}

Puting the value of r and \frac{dr}{dt}

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3 years ago
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