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3 years ago

A body oscillates with 25hz what is its time period

Physics

1 answer:

Semmy [17]3 years ago

4 0

Answer:

4 seconds

Explanation:

The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).

The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).

A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.

The period (T) is given as:

$Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds$

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If and then for example: If you get at least 6 hours of sleep, you will do better on tests than if you get less sleep.

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2 years ago

7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec

lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

$v=u+at$

where :

v is the final velocity of the ball

u is the initial velocity

a is the acceleration

t is the time elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

$a=3.5m/s^2$ is the acceleration

Solving for t, we find the time taken for this change in velocity:

$t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s$

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3 years ago

An object is made up of three masses connected by massless rods of fixed length. Mass A is located at (30.0 cm, 0 cm) and has a

puteri [66]

Answer:

0.0605 Kg m^2

Explanation:

In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin, we can just add three moment of inertia's .

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3 years ago

Which objects will likely have the greatest gravitational force between them?

Mariulka [41]

Answer:

d. Two soccer balls that are touching each other

Explanation:

Let $m_1$ be the mass of a tennis ball, $m_2$ is the mass of a soccer ball.

As the mass of a soccer ball is more than the mass of a tennis ball, so

$m_2 > m_1$

Let $d_1$ be the distance between the centers of both the balls near each other and $d_2$ be the distance between the centers of both the balls touching each other.

So, $d_2 > d_1$

The gravitational force, F, between the two objects having masses M and m and separated by distance d is

$F=\frac{GMm}{d^2}$

Where G is the universal gravitational constant.

As, the gravitational force is directly proportional to the product of both the masses and inversely proportional to the square of the distance between them, so selecting the larger mass ( $m_2$ , soccer ball) separated by a lesser distance ( $d_2$ , touching) to get more gravitational force.

Therefore, there will be a larger gravitational force between them when two soccer balls touching each other.

Hence, option (d) is correct.

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3 years ago

A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increas

Westkost [7]

To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words

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In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:

$\theta =$ 0 then our expression can be written as

$\Phi = BA$