<h2>A is the correct answer!</h2><h3></h3><h3>I'm too lazy to explain :(</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
A book containing information on various types of science related topics.
Answer : The heat capacity of the calorimeter is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of water = 
= specific heat of calorimeter = ?
= mass of water = 108.7 g
= mass of calorimeter = 108.7 g
= final temperature of mixture = 
= initial temperature of water = 
= initial temperature of calorimeter = 
Now put all the given values in the above formula, we get
Therefore, the heat capacity of the calorimeter is,
Answer:
A uniform meter rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm. ... When the balancing mass is moved then the resultant moment is the difference of clockwise moment and anticlockwise moment.
Answer:
v = 200.005 m / s
Explanation:
For this exercise we can use the concept of energy conservation,
Starting point. When the asteroid at h = 1000 km = 1 10⁶ m
Em₀ = K + U = ½ m v₀² - G m M / (R + h)
Final point. When the asteroid is on the surface of the moon
Emf = K + U = ½ m v² - G m M / R
As there is no friction the energy is conserved
Em₀ = Emf
½ m v₀² - G m M / (R + h) = ½ m v² - G m M / R
½ m (v₀² –v²) = G m M (-1 / R + 1 / R + h)
½ (v₀² - v²) = G M (-h / R (R + h))
v² = v₀² + 2 G M h / R (R + h))
Let's calculate
v² = 200² + 2 6.67 10⁻¹¹ 7.36 10²² / 1.74 (1.74 + 1 ))10¹²
v2 = 40000 + 2,059
v = 200.005 m / s
