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Goryan [66]
3 years ago
5

Water, h2o, is a molecule made of oxygen and hydrogen. the bonds that hold water molecules together are due to shared electrons,

and known as __________ bonds.a)covalent)dependent)ionic eliminated)nuclear

Chemistry
2 answers:
Dmitrij [34]3 years ago
8 0
Covalent bonds keep the hydrogen and oxygen atoms together
Jobisdone [24]3 years ago
4 0

Answer:

a) covalent

Explanation:

Atoms tend to gain, lose or share electrons to be more stable. Most atoms follow the octet rule, which states that atoms tend to complete its valence shell (last level of electrons) with 8 electrons. Oxygen follows this rule, but Hydrogen becomes stable when it has 2 electrons in its valence shell. H and O are non-metals, and they tend to share electrons to complete their valence shell.

Oxygen has 6 electrons in its last level, so it needs 2 electrons to complete its octet. Hydrogen has 1 electron so it needs 1 electron to complete its duet.

As a result, 1 atom of oxygen shares electrons with 2 atoms of hydrogen. This can be represented by a Lewis Structure (attached), where electrons are represented as points around each atom. Covalent bonds are formed by the pair of electrons shared between each pair of atoms. Therefore, in the molecule of water there are 2 covalent bonds.

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How many atoms of oxygen (O) are in one formula unit of Mg(NO3)2?
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5 0
3 years ago
Read 2 more answers
a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?
AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 790 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

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Therefore, the final pressure will be, 666.2 mmHg

6 0
2 years ago
A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylin
polet [3.4K]

Answer:

12.09 L

Explanation:

Step 1: Convert 826.1 mmHg to atm

We will use the conversion factor 760 mmHg = 1 atm.

826.1 mmHg × 1 atm/760 mmHg = 1.087 atm

Step 2: Convert 427.8 J to L.atm

We will use the conversion factor 101.3 J = 1 L.atm.

427.8 J × 1 L.atm/101.3 J = 4.223 L.atm

Step 3: Calculate the change in the volume

Assuming the work done (w) is 4.223 L.atm against a pressure (P) of 1.087 atm, the change in the volume is:

w = P × ΔV

ΔV = w/P

ΔV = 4.223 L.atm/1.087 atm = 3.885 L

Step 4: Calculate the final volume

V₂ = V₁ + ΔV

V₂ = 8.20 L + 3.885 L = 12.09 L

5 0
2 years ago
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