The reaction is
N₂O₄(g) <=> 2NO₂(g)
a. Initial pressure is 5.3 atm
We assume that the there is 1 mole at the start
N₂O₄(g) <=> 2NO₂(g)
1
-x 2x
---------------------------
1 - x 2x
The total moles is
1 + x
The mole fraction of N2O4 is
(1 - x)/(1 + x)
The mole fraction of NO2
2x/(1 + x)
Kp = [2x/(1 + x)]² / [(1 - x)/(1 + x)] = 0.25
Solve for x
And the total number of moles
The total pressure is solved by
(1 + x) (5.3)
The partial pressure of N2O4 is
5.3 (1 - x)
The partial pressure of NO4 is
5.3 (2x)
Do the same for the second problem.
Answer:
Fiber-rich, complex carbs
I believe it's gonna be B or C
Incomplete contribution happens when there is a limited supply of air so only half is much oxygen adds to the carbon forming carbon monoxide
