Answer:
-) 2-methylbut-2-ene
-) 2-methylbut-1-ene
-) 3-methylbut-1-ene
Explanation:
in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)
For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.
Answer:
One triple bond and four non bonding electrons
Explanation:
In considering the lewis structure of carbon monoxide, we must remember that the molecule contains a total of ten valence electrons. Four are the valence electrons that are present on the valence shell of carbon while six are the valence electrons on oxygen. Some of these valence electrons participate in bonding in the CO molecule.
Out of the six valence electrons on oxygen, two valence electrons participate in bonding with carbon while the other four electrons remain localized on the oxygen atom as two lone pairs of electrons.
Hence there are four nonbonding electrons in the lewis structure of CO as well as one triple bond.
decalescent energy-absorbing endothermal heat-absorbing endoergic.
Hope this helps!
Explanation:
The electrons in the outermost electron shell are responsible for forming chemical bonds. These electrons are also known as valence electrons
