Answer:
Explanation:
Percent composition of sodium chloride .
NaCl
Mol weight = 23 + 35.5 = 58.5 g
58.5 g of NaCl contains 23 g of Na
100 g of NaCl contains 23 x 100 / 58.5 g of Na
= 39.3 %
Na = 39.3 %
58.5 g of NaCl contains 35.5 g of Cl
100 g of NaCl contains 35.5 x 100 / 58.5 g of Na
= 60.7 %
Cl = 60.7 % .
The answer is B, early in the morning water covered areas (lakes,ponds,puddles,etc.) will vaporize a little bit because of the heat from the sun and it will continue all day, vapors rise towards the atmosphere and since it's a lot cooler there it will condense into a cloud which is full of tiny frozen water particles. Hope this helps <span />
Answer:
Explanation:
Hello there!
In this case, for these problem about the colligative property of freezing point depression, it is possible set up the following equation:
Whereas the van't Hoff's factor, i, is 2 since KCl is ionized in two ions (K+ and Cl-); and the molality (m) of the solution is computed by:
Thus, since the freezing point of water (ice) is 0°C, we obtain the following freezing point of the solution by plugging in:
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Answer: The vapor pressure of the solution is 55.2 torr
Explanation:
and
where, x = mole fraction in solution
= pressure in the pure state
According to Dalton's law, the total pressure is the sum of individual pressures.
x = mole fraction =
Given : 299 g of toluene and 391 g of benzene.
moles of toluene =
moles of benzene=
Total moles = moles of solute (toluene) + moles of solvent (benzene) = 3.25 + 5.01 = 8.26
= mole fraction of benzene =
=mole fraction of toluene = (1-0.39) = 0.61
Thus the vapor pressure of the solution is 55.5 torr