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Norma-Jean [14]
3 years ago
9

Consider a new peer Alice that joins BitTorrent without possessing any chunks. Without any chunks,she cannot become a top-four u

ploader for any of the other peers, since she has nothing to upload.How then will Alice get her first chunk?
Engineering
1 answer:
Airida [17]3 years ago
7 0

Answer:She will be selected by "Optimistic Unchoking".

Explanation:BitTorrent is a communication protocol for peer-to-peer file sharing (P2P) it is used to distribute data and electronic files over the Internet.

Optimistic unchoking is an important factor in BitTorrent peer-to-peer (P2P) file sharing networks, with optimistic unchocking there is always one peer that is unchocked.

BitTorrent Peers use optimistic unchoking to find the upload bandwidth details concerning other peers.

However, free users have been known to also make use of optimistic unchoking and download from the network without uploading anything.

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how are the construction steps for bisecting an angle similar to the steps you would have taken to construct and bisect a line s
GREYUIT [131]

Answer:

does the question entail anything else?

Explanation:

5 0
3 years ago
True or false a critique of hazwoper incidents that have occurred in the past year should not be included in hazwoper 8 hour ref
Jobisdone [24]

Answer:

False

Explanation:

No matter if something happened in the past year or so, it still should be included for safety reasons so it wont happen again

7 0
3 years ago
I really need help ASAP!!!
ValentinkaMS [17]

Explanation:

He would work on the thing like in the method you work on your question.

8 0
3 years ago
In the layout of a printed circuit board for an electronic product, 12 different locations can accommodate chips.
iren [92.7K]

Answer:

a) 244,140,625 different ways

b) 390,625 different ways

Explanation:

a) If there are 5 ways to place a chip on each location, and there are 12 locations overall, we have:

5^12 ways of placing them

This would mean a total of 244,140,625 different ways

b) If five chips are of the same type, we can first find how many ways we can place chips on the remaining 7 locations:

5^7 = 78,125

Next we can multiply this by the number of ways the next 5 chips could be the same:

78,125 * 5 = 390,625 different ways

4 0
3 years ago
Three communications channels in parallel have independent failure modes of 0.1 failure per hour. These components must share a
ozzi

Answer:

the MTTF of the transceiver is 50.17

Explanation:

Given the data in the question;

failure modes = 0.1 failure per hour

system reliability = 0.85

mission time =  5 hours

Now, we know that the reliability equation for this situation is;

R(t) = [ 1 - ( 1 - e^{-0.1t )³] e^{-t/MTTF

so we substitute

R(5) = [ 1 - ( 1 - e^{-0.1(5) )³] e^{-5/MTTF = 0.85

[ 1 - ( 1 - e^{-0.5 )³] e^{-5/MTTF = 0.85

[ 1 - ( 0.393469 )³] e^{-5/MTTF = 0.85

[ 1 - 0.06091 ] e^{-5/MTTF = 0.85

0.9391 e^{-5/MTTF = 0.85  

e^{-5/MTTF = 0.85 / 0.9391

e^{-5/MTTF = 0.90512

MTTF = 5 / -ln( 0.90512 )

MTTF = 50.17

Therefore, the MTTF of the transceiver is 50.17

7 0
3 years ago
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