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Nitella [24]
2 years ago
10

How much thermal energy is needed to raise the temperature of 15kg gold from 45⁰ C up to 80⁰ C​

Engineering
1 answer:
Levart [38]2 years ago
6 0

Answer:

68.25 kJ

Explanation:

The thermal energy Q required to raise the temperature of 15kg gold from 45⁰ C up to 80⁰ C​ is Q = mcΔθ where m = mass of gold = 15 kg, c = specific heat capacity of gold = 130 J/kg°C and Δθ = temperature change = θ₂ - θ₁ where θ₁ = 45 °C and θ₂ = 80 °C

So, Q = mcΔθ = mc(θ₂ - θ₁)

= 15 kg × 130 J/kg°C × (80 °C - 45 °C)

=  1950 J/°C × 35 °C

= 68,250 J

= 68.25 kJ

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Answer

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Explanation:

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2 years ago
In an experiment, the local heat transfer over a flat plate were correlated in the form of local Nusselt number as expressed by
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Answer:

\dfrac{\bar{h}}{h}=\dfrac{5}{4}

Explanation:

Given that

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Nu_x=0.035Re_x^{0.8} Pr^{1/3}

Nu_x=0.035\times\left(\dfrac{\rho vx}{\mu}\right)^{0.8}Pr^{1/3}

All other quantities are constant only x is a variable in the above equation .so lets take all other quantities as a constant C

Nu_x=C.x^{0.8}=C.x^{4/5}

We also know that

Nux=hx/K

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h=mx^{-1/5}

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The average value of h given as

\bar{h}=\dfrac{\int_{0}^{L}hdx}{L}

\bar{h}=\dfrac{5m}{4}\times\dfrac{L^{4/5}}{L}

\bar{h}=\dfrac{5m}{4}L^{-1/5}             ---------1

The value of local heat transfer coefficient at x=L

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From 1 and 2 we can say that

\dfrac{\bar{h}}{h}=\dfrac{5}{4}

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Explanation:

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  1. Telephone
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According to O*NET, the common work contexts for Licensing Examiners and Inspectors include:

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