Answer:
B.
Explanation:
The only way to make this comparison is by comparing their position to a fixed object outside the vehicle. Comparing to a fixed object inside the vehicle will show no movement, while a moving object inside the vehicle will seem as though the car is still while the object is in motion. Comparing to a moving object outside the vehicle will conflict with the vehicle, if the object is moving at the same speed and direction as the vehicle, it will seem as though neither is moving. The only way to make this comparison correctly is by comparing to an object outside the vehicle that is not moving so that the only variable that can be moving is the vehicle itself.
Ba2Cl
NaS2
The numbers are in subscript
Answer:
A) CaCO₃
C) No precipitate
Explanation:
To answer these questions we need to consider the solubility rules.
<em>Identify the precipitate or lack thereof for the following:</em>
CaCl₂(aq) + K₂CO₃(aq) ⇒ CaCO₃(s) + 2 KCl(aq)
- Group II carbonates are insoluble. Thus, CaCO₃ is insoluble.
- Salts containing Group I cations are soluble. Thus, KCl is soluble.
FeCl₂(aq) + (NH₄)₂SO₄(aq) ⇒ FeSO₄(aq) + 2 NH₄Cl(aq)
- Most sulfates are soluble. Thus, FeSO₄ is soluble.
- Salts containing the ammonium ion are soluble. Thus, NH₄Cl is soluble.
First, we can see that the output is a salt and water which means that the reactants were an acid and a base. Since the given reactant is a base, thus, NH4OH is excluded as it is also a base.
Now, examining the outputs of the reactions, we will find that they are composed mainly of sodium, hydrogen, oxygen and carbon. This excludes H3PO4 as it contains phosphorus.
The last step is to compare between the number of moles of each element in the output with those in the input. The output has 1 sodium mole, 2 carbon moles, 5 hydrogen moles and 3 oxygen moles.
The given input (NaOH) has 1 sodium, 1 oxygen and 1 hydrogen moles. Therefore, the other input (reactant) should have 2 carbon, 4 hydrogen and 2 oxygen moles.
Based on this, the right solution is CH3COOH.