<span>The notation is not written in the correct order as the 4s subshell should appear before the 3d subshell.
</span>The correct order in an electron configuration would be:
1s , 2s , 2p , 3s , 3p , 4s , 3d , 4p , 5s , 4d , 5p , 6s , 4f , 5d , 6p ,..
So, for germanium the electronic configuration should be;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p²
Answer:
(Fe(OH)2 + Na2SO4
Explanation:
Iron (II) hydroxide precipitate. Iron (II) hydroxide precipitate (Fe(OH)2) formed by adding few drops of a 1M solution of sodium hydroxide (NaOH) to 0.2 M solution ferrous sulfate (FeSO4). The reaction is FeSO4 + NaOH -> Fe(OH)2 + Na2SO4. This is an example of a double replacement reaction. Pure iron (II) hydroxide is white, however even trace amounts of oxygen make it greenish.
The answer is C
explanation
Answer:
the molecular formula of the compound is N2O4
Explanation:
- Find the empirical formula
mole of N present = mass of N divided by molar mass of N = 0.140/14 = 0.01 mole
mole of O present = mass of O divided by molar mass of O = 0.320/16 = 0.02 mole
Divide both by the smallest number of mole to determine the coefficient of each, the smallest number of mole is 0.01 thus:
quantity of N = 0.01/0.01 = 1
quantity of O = 0.02/0.01= 2
thus the empirical formula = NO2
- Now determine the molecular formula by finding the ratio of molecular formula and empirical formula
Molar mass of molecular formula = 92.02 amu = 92.02 g/mole
Molar mass of empirical formula NO2 = (14 + (16 x 2)) = 46 g/mole
the x factor = 92.02/46 = 2
Molecular formula = 2 x NO2 = N2O4
