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3 years ago

Using algebra tiles, form a rectangle to represent each of the following

Mathematics

1 answer:

RideAnS [48]3 years ago

3 0

Answer:

Answer is below

Step-by-step explanation:

I graphed all of the expressions on the graph below to find the solutions of the expressions.

If these answers are correct, please make me Brainliest!

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Please help!!!!!!!!!

Harlamova29_29 [7]

Answer:

10.3

Step-by-step explanation:

$\sqrt{ { ( 8 - ( - 1))}^{2} + {( - 2 - 3)}^{2} } = \sqrt{ {9}^{2} + {( - 5)}^{2} } = \sqrt{81 + 25} = \sqrt{106} = 10.3$

(Army?

5 0

2 years ago

Which answer is the correct form of bar notation for this decimal number: 4.676767…

Rudiy27

Hello There!

Well all of your answer options are the same so i suppose they are all right.

Hope This Helps You!
Good Luck :)

4 0

3 years ago

Read 2 more answers

Which set or sets does the number 15 belong to

DENIUS [597]

Rational,real,integer,whole number,natural number

3 0

2 years ago

Uhhhh last question lol I have to match them

Anarel [89]

Answer:

7. is 5 - 35n

8. is -6x - 24

9. is 15m - 30

10. is 24p - 28

11. is 5b - 5

12. 5x + 45

RULE:

WHEN MULTIPLYING TWO NEGATIVES YOU WILL GET POSITIVE.

IF ONE IS NEGATIVE AND THE OTHER IS POSITIVE WHEN MULTIPLYING IT WILL BE NEGATIVE.

WHEN MULTIPLYING TWO POSITIVE NUMBERS IT WILL ALWAYS BE POSITIVE

SAME THING IF YOU MULTIPLY A POSITIVE NUMBER WITH A NEGATIVE NUMBER YOU GET A NEGATIVE AS YOUR ANSWER

YOU NEED ONE SIGN OF THE SAME WHEN MULTIPLYING TO BE A POSITIVE AS YOUR ANSWER

YOU NEED ONE SIGN TO BE DIFFERENT FROM THE OTHER WHEN MULTIPLYING TO GET A NEGATIVE AS YOUR ANSWER

4 0

3 years ago

Read 2 more answers

A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate

Mrrafil [7]

Answer:

a: 0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70. The sample size, n = 125.

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317. We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0

2 years ago