Answer:
Buffalo mild wings offers the lowest price per wing ($0.83).
Step-by-step explanation:
Let us find unit price per buffalo wing of each restaurant.


Upon rounding our answer to nearest cent we will get,

Therefore, buffalo bills offers each wing for $0.88.


Upon rounding our answer to nearest cent we will get,

Therefore, buffalo mild wings offers each wing for $0.83.


Therefore, wingers offers each wing for $0.85.
We can see that buffalo mild wings offers the lowest price per wing that is $0.83 per wing.
Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:
<em>y</em> = -1 - <em>x</em> ==> <em>x</em> = -1 - <em>y</em>
<em>y</em> = <em>x</em> - 1 ==> <em>x</em> = 1 + <em>y</em>
So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.
This means the area is given by the integral,

The integral with respect to <em>x</em> is trivial:

For the remaining integral, integrate term-by-term to get

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.
It should be a 10% tip. To simplify the answer, The decimal moves one space (which would be equal to a tenth) so it’s a 10%
Just put it over 100
Example 0.45 = 45/100