Answer:
- The smallest area the field could be is 6,400 m²
- The largest area the field could be is 8,250 m²
Step-by-step explanation:
Given;
smallest possible length of the international soccer field, L₀ = 100 m
smallest possible breadth of the international soccer field, B₀ = 64 m
Largest possible length of the international soccer field, L₁ = 110 m
Largest possible breadth of the international soccer field, B₁ = 75 m
Area of a rectangle is given by;
A = L x B
The smallest area the field could be is calculated as;
A₀ = L₀ x B₀
A₀ = 100 m x 64 m
A₀ = 6,400 m²
The largest area the field could be is calculated as;
A₁ = L₁ x B₁
A₁ = 110 m x 75 m
A₁ = 8,250 m²
Elevator 1 is 12 ft above ground level...and elevator 2 is 15 ft below ground level
The answer is 3.46 meters
You can get the answer by using the pythagorean theorem, since the ladder and the wall form a right triangle.
c^2 = a^2 + b^2
4^2 = 2^2 + b^2
16 = 4 + b^2
12 = b^2
b = sqrt(12) or 3.46 meters
Answer:
answer is 0
Step-by-step explanation:
