Answer:
0.54m
Explanation:
Step one:
given data
length of seesaw= 3m
mass of man m1= 85kg
weight = mg
W1= 85*10= 850N
mass of daughter m2= 35kg
W2= 35*10= 350N
distance from the center= (1.5-0.2)= 1.3m
Step two:
we know that the sum of clockwise moment equals the anticlockwise moment
let the distance the must sit to balance the system be x
taking moment about the center of the system
350*1.3=850*x
455=850x
divide both sides by 850
x=455/850
x=0.54
Hence the man must sit 0.54m from the right to balance the system
Assuming motion is on a straight path, the result of two positive components of a vector would also be a positive value since both are having positive signs and directions. The direction would be the same with the motion as well. Hope this answers the question. Have a nice day.
Answer:
W = 3.1 N
Explanation:
moments about any convenient point will sum to zero.
I choose summing about the knife edge mark and will assume the ruler of weight W is of uniform construction.
I will assume the ruler weight makes a positive moment
W[55 - 50) - 0.040(9.8)[ 95 - 55] = 0
5W = 15.68
W = 3.136
The most probable answer for this question would be that almost every life process requires specialized cells in multicellular organisms. To simply put it, cells of multicellular organisms are specialized in a way that they are all grouped into their respective tissues and these tissues are all grouped into their respective organs and these organs are all grouped together into their respective systems and these systems make up the multicellular organisms. These systems have their own functions in maintaining and sustaining the life that the organisms has. The organs have their own functions as well, thus specialized cells are mostly needed in respiration, digestion, circulation, movement, excretion, reproduction, immunity, coordination, and synthesis.
10.3
Explanation:
Step 1:
The pressure exerted by any liquid column of height, h density d is given by the formula P = h * d * g
Step 2:
It is given that one atmosphere pressure pushes up 76.0 cm of mercury, we need to calculate the level of water that will be pushed by the same pressure.
Step 3:
Since the pressure pushing up mercury and water is the same
* 
* g = 
* 
* g
= 
= (13.6 g/cm * 76 cm)/1 g/cm = 1033.6 cm
Step 4:
Now we need to express the answer in meters.
1 m = 100 cm.
1033.6 cm = 10.336 m
This can be rounded off to 10.3 m
