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Dafna11 [192]
3 years ago
9

You have decided to walk in a long-distance race. There are two teams that you can join. Team A walks at a constant rate of 2.5

miles per hour. Team B walks 4 miles the first hour and then 2 miles per hour after that.
Mathematics
1 answer:
velikii [3]3 years ago
6 0

Where is the question?? I'll be glad to answer in the comments once the question is given. Hope to hear from you!

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(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript
stiks02 [169]
\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}


Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}
6 0
3 years ago
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Given: ​△ACE, BD​∥AE<br><br> Prove: BA/CB=DE/CD<br><br> Drag
gizmo_the_mogwai [7]

Answer:


Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2        Corresponding angles for two        parallel lines BD and AE

Triangle AED ||| BDE                                       Angle angle congruent

...                                                                       By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

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A ladder leans against the wall and reaches a
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The base would represent the side adjacent to the angle and the height up the wall would be the opposite side. Using the tangent^-1 (opposite over adjacent) function we are looking for the tan^-1 of 6/24 or 14.04°
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lbvjy [14]

Answer:

The answer is25th August

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