Answer:
a) 0.61 mol
Explanation:
165.3718 g Rubidium Bromide = 1 mol
100 g Rubidium Bromide = 1/165.3718 x 100
= 0.61 mol
Answer:
The boiling point is somewhere between 56 and 151 °C
Explanation:
Hello,
In this case, it is possible to compute it via rigorous methods in phase equilibrium by using for example a cubic equation of state to model the vapor phase and a suitable excess Gibbs free energy model for the liquid phase, nonetheless, it is an arduous task. In such a way, since the information about both acetone's and nonane's pure boiling points is given as well as acetone's mole fraction, which points out it is about a binary liquid solution, one could make up the boiling point is somewhere between 56 and 151 °C precising that it should be closer to 151 °C as the mixture is 90% nonane and 10% acetone.
Best regards.
Answer:
First ionization of lithium:
.
Second ionization of lithium:
.
Explanation:
The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:
- Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol next to any atom or ion in the equation.
- The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
- Charge shall balance on the two sides of the equation.
First Ionization Energy of Li:
- The products shall contain a gaseous ion with charge +1 as well as an electron .
- Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: .
- Hence the equation: .
Second Ionization Energy of Li:
- The product shall contain a gaseous ion with charge +2: as well as an electron .
- Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?
- The equation for this process is .
The two compounds present
in unpolluted air are carbon dioxide and water. You may think that carbn
dioxide is a greenhouse gas, yes it is and at the same time not. There animals
in the earth that produces carbon dioxide into the atmosphere, the carbon
dioxide too, is also need for plan respiration.
Answer:
2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.
Explanation:
Generally, moles of solute in solution before dilution must equal moles of solute after dilution.
By definition Molarity = moles solute/volume of solution in Liters
=> moles solute = Molarity x Volume (L)
Apply moles before dilution = moles after dilution ...
=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution
=> (M)(2.5L)before = (1.2M)(10.0L)after
=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate