Answer: yes, it is
Step-by-step explanation:
A number is divisible by 6 if it is divisible by 2 and 3 simultaniously.
n = k(k+1)(k-1)
If k-1 is a multiple of 3, n is divisible by 3, so one of the requirements is ok.
Now, if k-1 is a multiple of 3, it can be even or odd.
if k-1 is even, then it is divisible by 2 and as it is divisible by 3 as well, n is divisible by 6
if k-1 is odd, then k and k+1 is even, hence, divisible by 2.
As n = k(k+1)(k-1), n is also divisible by 6.
Answer:
Step-by-step explanation:
Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula

Here's what we have:
The amount after a certain time that she has in the bank is 4672.12; that's A(t).
The interest rate in decimal form is .18; that's r.
The number of times the interest compounds is 12; that's n
and the time that the money is invested is 3.5 years; that's t.
Filling all that into the formula:
Simplifying it down a bit:
Raise 1.015 to the 42nd power to get
4672.12 = P(1.868847115) and divide to get P alone:
P = 2500.00
She invested $2500.00 initially.
Answer:
b
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
56=7-3[4+{8-4(4+5-3)}]
56=7-3[4+{4(4+5-3)}]
56=7-3[4+{16+20-12)}]
56=7-3[4+24]
56=4[28]
56=92
56-56=92-56
36
Answer:

Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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