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The specific heat of water is 4.2 J/g • °C. How much heat is required to raise the temperature of 100 g of water by 5°C? *

Svetach [21]

Answer:

2100 J

Explanation:

The heat required to increase the temperature of a substance is given by

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is its change in temperature

For the water in this problem, we have:

m = 100 g is its mass

C = 4.2 J/g • °C is the specific heat capacity

$\Delta T=5^{\circ}C$ is the increase in temperature

So, the amount of heat needed is:

$Q=(100)(4.2)(5)=2100 J$

7 0

3 years ago

If a thief jumps from the tried floor of a house while holding a box on

Ksju [112]

What do you mean? it doesn't make sense

7 0

3 years ago

Read 2 more answers

A string fixed at both ends is 8.40 m long and has a mass of 0.120 kg. It is subjected to a tension of 96.0 N and set oscillatin

Luden [163]

Answer:

81.9756 m/s

16.8 m

4.8795 Hz

Explanation:

m = Mass of string = 0.12 kg

L = Length of string = 8.4 m

T = Tension on string = 96 N

Linear density is given by

$\mu=\dfrac{m}{L}\\\Rightarrow \mu=\dfrac{0.12}{8.4}$

Spee of the wave is given by

$v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{96}{\dfrac{0.12}{8.4}}}\\\Rightarrow v=81.9756\ m/s$

The speed of the waves on the string is 81.9756 m/s

Wavelength is given by

$\lambda=2L\\\Rightarrow \lambda=2\times 8.4\\\Rightarrow \lambda=16.8\ m$

The longest possible wavelength is 16.8 m

Frequency is given by

$f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{81.9756}{16.8}\\\Rightarrow f=4.8795\ Hz$

The frequency of the wave is 4.8795 Hz

3 0

4 years ago

A 2.0-μF capacitor and a 4.0-μF capacitor are connected in series across a 1.0-kV potential. The charged capacitors are then dis

vekshin1

Answer:

Explanation:

Given that,

We have two capacitors connected in series

C1=2.0-μF

C2=4.0-μF

Then the equivalent of their series connection

1/Ceq = ½ + ¼

1/Ceq= (2+1)/4

1/Ceq=¾

Taking the reciprocal

Ceq= 4/3 μF

The capacitors are connected to a battery of 1kv

V=1000Volts

We know that,

Q=CV

Where Q is charge

C is capacitance and

V is voltage

Then, Q=4/3 ×1000

Q=4000/3 -μC

Since the capacitors are in series, then the charge pass through them, so each charge on the capacitors are 4000/3 μF

After the capacitor has been charge, the capacitor are disconnect and reconnected in parallel to each other,

For parallel connection, they have the same voltage but different charges.

When connected in parallel, there is a charge redistribution,

And the total charge will be 2•4000/3=8000/3 -μF

Then, Q1 +Q2= 8000/3 μF

Now the charge on each capacitor will be, let them have a common voltage V

Q=CV

Then, Q1=C1V

Q1= 2×V=2V

Q2= 4×V=4V

Then, Q1+Q2=8000/3

4V+2V=8000/3

6V=8000/3

V=8000/(3×6)

V=4000/9

V=444.44Volts

Now, Q1=2V

Q1=2×4000/9

Q1=8000/9 μF

Also, Q2=4V

Q2=4×4000/9

Q2=16000/9 μF

4 0

3 years ago

Which best describes longitudinal waves?

RUDIKE [14]

The right answer for the question that is being asked and shown above is that: "A. Compressions and rarefactions make up longitudinal waves, which can only travel in matter." The statement that best describes longitudinal waves is that c<span>ompressions and rarefactions make up longitudinal waves, which can only travel in matter.</span>

3 0

3 years ago