Answer:
Yes. Gravity is 90% of what it is on the earth's surface. ISS moves at such high speeds that the curve of its fall will always match the curve of the earth and so will never hit the earth.
Explanation:
The location of the International Space Station (ISS) is at an altitude of about 200 or 250 miles above the earth's surface. Since gravity decreases with altitude, it is less at that height. Gravity is still present there. Since the ISS is in orbit around the earth, the condition is of free fall. Result of this free fall is apparent weightlessness. The high speed of the ISS allows it to orbit around in such a way that the gravitational pull of the earth is equal to the centripetal force experienced by the ISS in its orbit.
The conditions which make it remain in space are similar to how the moon stays in the orbit around the earth. Moon is also in free fall but it never falls down to earth.
Answer:
zero displacement
its returnin to the starting point.
5 north 5 south
Answer:
x = 12cm
Explanation:
First, with the values given for the force and the displacement, you calculate the spring-constant of the dynamometer by using the following equation (primero, con los valores dados de la fuerza y el desplazamiento, calculas la constante del resorte aplicando la siguiente formula):
F: force (fuerza) = 10N
k: spring constant (constante del resorte)
x: displacement of the spring (desplazamiento del resorte) = 6cm
by using these values you calculate k (usando estos valores calculas k):
With this value you calculate the displacement for a force of 20N (con este valor de k calculas el desplazamiento del resorte para una fuerza de 20N):
hence, the displacement is 12cm
Im pretty sure the answer would be A
