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Nostrana [21]
3 years ago
10

In the simulation above, as the projectile travels upward, how does the vertical velocity change? Vertical velocity is zero. Ver

tical velocity decreases. Vertical velocity increases. Vertical velocity remains the same.
Physics
2 answers:
PolarNik [594]3 years ago
7 0

the vertical velocity decreases.

Butoxors [25]3 years ago
5 0

Answer:

Vertical velocity decreases.

Explanation:

The figure of the simulation is missing, however we can still answer. In fact, the problem tells us that the projectile is moving upward. We are only interested in the vertical velocity of the projectile, so we can consider only its vertical motion.

The vertical motion of the projectile is an accelerated motion, with constant acceleration g = 9.8 m/s^2, directed downward (acceleration due to gravity). The problem says that the projectile is still moving upward, so its velocity is directed upward. This means that the vertical acceleration is in the opposite direction of the vertical velocity: therefore, the vertical velocity must be decreasing, according to the equation

v(t)=v_0 -gt

where v0 is the initial vertical velocity of the projectile, and t the time. Due to the negative sign in the formula, we see that as t increases, v(t) decreases.

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Two point sources are simultaneously creating waves with a wavelength of 6 cm. Point X lies between the two sources. It is 9 cm
jok3333 [9.3K]

Answer:

OPTION D (The waves will sometimes get very high and very low) is the answer.

Explanation:

Wavelength = velocity ÷ frequency

As the frequency which measures the number of waves per unit of time is inversely proportional to the wavelength, point X which lies between two sources, and one source is shorter than another, the wave heights at point x will vary as the distances from point X vary too. This means that waves at point X depending on the wave type and source will get very high at times and very low.

                                                   

6 0
3 years ago
A object of mass 33 is dropped from a height of 85 meters. Calculate the average power developed by the object in falling throug
DochEvi [55]
Power  =  Work done  /  Time taken.

Work done =  mgh
Mass, m = 33kg    ( Am presuming it is 33 kg).
h =  85 m.
Work done =  33 * 9.81* 85 =  27517.05  J.

Time taken.
Since object was dropped from height, it fell under gravity.
Using    H =  ut  +  (1/2) * gt^2.              u = 0.
               H =  1/2 gt^2.
               t  =   (2H/g) ^ (1/2)
               t  =  (2*85/9.81) ^ 0.5 =  4.1628 s.

Power  =    27517.05 / 4.1628 = 6610.23 Watts.
             =  6610 W  to  3 S. f.

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3 years ago
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irga5000 [103]

Answer:

on and off

Explanation:

if there are switches, it can change if the electricity can get to the bulb or not. if it appears that there is no pathway for the electricity to get to the light bulb, it is of, if there is a pathway, its on

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The answer is d hope this helps
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I NEED THIS A SOON AS POSSIBLE
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3 years ago
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