Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.
For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.
So, using the formula: Circumference = 2πr = <span>πd
Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
Is there a certain context to this question so that I can answer it better?
A) The ball on the small ball is far smaller than the force on the basketball.
B) The total momentum before and after the collision remains constant.
C) We know momentum is conserved so we do:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.1 x 5 + 0.6 x 0 = 0.1 x -4 + 0.6 x v₂
v₂ = 1.5 m/s
Answer:
Induced emf in the loop is 0.02208 volt.
Induced current in the loop is 0.0368 A.
Explanation:
Given that,
Area of the single loop, 
The initial value of uniform magnetic field, B = 3.8 T
The magnetic field is decreasing at a constant rate, 
(a) The induced emf in the loop is given by the rate of change of magnetic flux.

(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :

Hence, this is the required solution.