Answer:
Q=185.84C
Explanation:
We have to take into account the integral

In this case we have a superficial density in coordinate system.
Hence, we have for R: x2 + y2 ≤ 4

but, for symmetry:
![Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C](https://tex.z-dn.net/?f=Q%3D4%5Cint_0%5E2%5Cint_0%5E%7B%5Csqrt%7B4-x%5E2%7D%7D%5Crho%20dydx%5C%5C%5C%5CQ%3D4%5Cint_0%5E2%5Cint_0%5E%7B%5Csqrt%7B4-x%5E2%7D%7D%284x%2B4y%2B4x%5E2%2B4y%5E2%29%20dydx%5C%5C%5C%5CQ%3D4%5Cint_0%5E%7B2%7D%5B4x%5Csqrt%7B4-x%5E2%7D%2B2%284-x%5E2%29%2B4x%5E2%5Csqrt%7B4-x%5E2%7D%2B%5Cfrac%7B4%7D%7B3%7D%284-x%5E2%29%5E%7B3%2F2%7D%5Ddx%5C%5C%5C%5CQ%3D4%5B46.46%5D%3D185.84C)
HOPE THIS HELPS!!
m = Q(on moon) * G(on moon) = 200N * 1.63N/kg = 326kg
Q(Earth)= g * m = 10m/s2 * 326kg = 3260N
i dont get it so much but
The weight of the bag pack is 8.2 N. g = 1.64 m/s2. Hence, the acceleration due to gravity on moon is 1.64 m/s2. sooo? is it right
Answer:
Humus
Explanation:
Its Humus I believe. I remember learning something like this.
Answer:
Explanation:
radius of hoop and the radius of disk is same = R
Let the mass of hoop is M and the mass of disk is M'.
As they reach the bottom of teh surface in same time so they travel equal distance thus, they have same acceleration.
The acceleration is given by

As the acceleration is same so that the moment of inertia is also same.
Moment of inertia of disk = moment of inertia of hoop
1/2 x mass of disk x R² = mass of hoop x R²
So, mass of disk = 2 x mass of hoop
Option (c) is correct.