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labwork [276]
3 years ago
9

A train crew was cleaning out a rail tanker that had been emptied of its contents. They rinsed the rail car out with scalding ho

t water through a port of the bottom of the rail car. When they were finished and had drained the water out they shut the valve of the port and went home for the day. During the night the temperature droppe d and it was very cold outside. When they came back to the work the next night something happens to the rail car!

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

...............

.

......

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Coming to the bottom of a mountain, a skier moving with speed v collides with a barrier and is brought to a stop in an amount of
IRISSAK [1]

Answer:

Explanation:

Impulse of a force is measured by force x time or F X t

Impulse also equals change in momentum or

F x t = m v₂ - m v₁

The given case is as follows

in the first case

F x t = mv - o = mv

F = mv / t

in the second case

F₁ x 4 t = mv

F₁ = 1/4 x mv /t

F₁ = F / 4

option a) is correct .

iii )

In the last case

F₂ X t = m v/2 -0

F₂ = 1/2 x mv / t

= 1/2 x F

F₂ = F/2

Option e ) is correct.

8 0
3 years ago
Amanda goes shopping for light bulbs. In the light bulb aisle, she finds the following incandescent light bulbs. Can you help he
Luden [163]

Answer:

The least efficient light bulb is the first one (25 W - 210 Lumen)

Explanation:

Efficiency can be defined as what you want to obtain over what you need to produce it. In this case Eff= Wattage / Lumen. For each light bulb, their efficiency is: 8.4 / 11.12 / 15.7 Lum/W

4 0
3 years ago
A stone tumbles into a mine shaft strikes bottom after falling for 4.2 seconds. How deep is the mine shaft
ziro4ka [17]
d = u \times t \: + \frac{1}{2} \times a \times {t}^{2}
Since initial velocity is zero hence , u = 0

=> d = 1/2 * a * t2

d = 0.5 \times 9.8 \times {4.2}^{2}
on solving we get

d = 86.436 metres


Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2
3 0
4 years ago
An ambulance is rapidly approaching you at a stop light. What happens to the frequency and pitch of the sound as the ambulance d
vagabundo [1.1K]

Answer:

A )

Explanation:

This change in frequency observation occur due to doppler effect

if the wave source moves,In the time between one wave peak being emitted and the next, the source will have moved so that the shells will no longer be concentric. The wavefronts will get closer together in front of the source as it travels and will be further apart behind it.  (see the graph)

when the person standing still in front of the ambulance, he will observe a <em>higher frequency </em>than before as the source travels towards them.

f_(observed)=\frac{V_(wave)}{V_(wave)-V_(source)} *f_(original)

The pitch we hear depends on the frequency of the sound wave.

A high frequency corresponds to a high pitch

as we hear a higher frequency , it makes the <em>pitch higher</em> too

5 0
3 years ago
Read 2 more answers
In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot
Fittoniya [83]

Answer:

Q=7.9\times 10^{-10}\ C

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

A=5\times 10^{-3}\ m^2

We Capacitance given as

For air

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{\varepsilon _oA}{d}

C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}

C_1=2.2\times 10^{-11}\ F

C_2=\dfrac{K\varepsilon _oA}{d}

C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F

C_2=6.6\times 10^{-11}\ F

Net capacitance

C=C₁+C₂

C=8.8\times 10^{-11}\ F

We know that charge Q given as

Q= C V

Q=12\times 6.6\times 10^{-11}\ C

Q=7.9\times 10^{-10}\ C

6 0
3 years ago
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