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2 years ago

1. The surface considered for Gauss’s law is called

Physics

2 answers:

lidiya [134]2 years ago

5 0

Answer:

C) Gaussian surface

Explanation:

geniusboy [140]2 years ago

4 0

Answer:

Explanation:

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What happens to the frequency of a wave of you increase the speed of the wave ?

exis [7]

Nothing happens. The frequency is determined at the source,
and it doesn't change along the way.

3 0

3 years ago

An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1

Ksivusya [100]

<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

$F=\frac{GMm}{r^2}$

Where G = 6.67 x 10⁻¹¹ N m²/kg²

M = Mass of body 1

M = Mass of body 2

r = Distance between them

Here we have

M = Mass of Sun = 1.99×10³⁰ kg

m = Mass of asteroid = 4.00×10¹⁶ kg

F = 3.14×10¹³ N

Substituting

$F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m$

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0

3 years ago

What other uses does petroleum have besides being used for fuel and lubricants

Alborosie

the answer i think is asphalt and plastic

7 0

3 years ago

A glass tube 1.50 meters long and open at one end is weighted to keep it vertical and is then lowered to the bottom of a lake. W

Lilit [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The total pressure is $P_T = 10.79*10^{5} N/m^2$

The temperature at the bottom is $T_b = 284.2 \ K$

Explanation:

From the question we are told that

The length of the glass tube is $L = 1.50 \ m$

The length of water rise at the bottom of the lake $d = 1.33 \ m$

The depth of the lake is $h = 100 \ m$

The air temperature is $T_a = 27 ^oC = 27 +273 = 300 \ K$

The atmospheric pressure is $P_a = 1.01 *10^{5} N/m$

The density of water is $\rho = 998 \ kg/m^3$

The total pressure at the bottom of the lake is mathematically represented as

$P_T = P_a + \rho g h$

substituting values

$P_T = 1.01*10^{5} + 998 * 9.8 * 100$

$P_T = 10.79*10^{5} N/m^2$

According to ideal gas law

At the surface the glass tube not covered by water at surface

$P_a V_a = nRT_a$

Where is the volume of

$P_a *A * L = nRT_a$

At the bottom of the lake

$P_T V_b = nRT_b$

Where $V_b$ is the volume of the glass tube not covered by water at bottom

and $T_b$ i the temperature at the bottom

So the ratio between the temperature at the surface to the temperature at the bottom is mathematically represented as

$\frac{T_b}{T_a} = \frac{d * P_T}{P_a * h}$

substituting values

$\frac{T_b}{27} = \frac{0.133 * 10.79 *10^5}{1.01 *10^{5} * 1.5}$

=> $T_b = 284.2 \ K$

3 0

3 years ago

He starter motor of a car engine draws a current of 170 AA from the battery. The copper wire to the motor is 6.00 mmmm in diamet

sweet-ann [11.9K]

Answer:

129.2 C

0.33758239177 mm

Explanation:

n = Number density = $8.46\times 10^{28}\ electrons/m^3$

i = Current = 170 A

t = Time taken = 0.76 s

d = Diameter = 6 mm

Charge is given by

$q=it\\\Rightarrow q=170\times 0.76\\\Rightarrow q=129.2\ C$

The charge passing throught the motor is 129.2 C

Current density

$J=\dfrac{i}{A}\\\Rightarrow J=\dfrac{170}{\dfrac{\pi}{4}\times (6\times 10^{-3})^2}\\\Rightarrow J=6012520.07236\ A/m^2$

Drift velocity is given by

$v_d=\dfrac{J}{ne}\\\Rightarrow v_d=\dfrac{6012520.07236}{8.46\times 10^{28}\times 1.6\times 10^{-19}}\\\Rightarrow v_d=0.000444187357592\ m/s$

Distance traveled

$s=v_dt\\\Rightarrow s=0.000444187357592\times 0.76\\\Rightarrow s=0.00033758239177\ m=0.33758239177\ mm$

The electron traveled 0.33758239177 mm

8 0

3 years ago