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iren [92.7K]
2 years ago
5

1. The surface considered for Gauss’s law is called

Physics
2 answers:
lidiya [134]2 years ago
5 0

Answer:

C) Gaussian surface

Explanation:

geniusboy [140]2 years ago
4 0

Answer:

c

Explanation:

You might be interested in
What happens to the frequency of a wave of you increase the speed of the wave ?
exis [7]

Nothing happens.  The frequency is determined at the source,
and it doesn't change along the way.


3 0
3 years ago
An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1
Ksivusya [100]
<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

                 F=\frac{GMm}{r^2}

           Where G =  6.67 x 10⁻¹¹ N m²/kg²

                       M = Mass of body 1

                       M = Mass of body 2

                       r = Distance between them

Here we have

                 M = Mass of Sun = 1.99×10³⁰ kg

                 m = Mass of asteroid = 4.00×10¹⁶ kg

                 F = 3.14×10¹³ N

Substituting

                   F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0
3 years ago
What other uses does petroleum have besides being used for fuel and lubricants
Alborosie
the answer i think is asphalt and plastic
7 0
3 years ago
A glass tube 1.50 meters long and open at one end is weighted to keep it vertical and is then lowered to the bottom of a lake. W
Lilit [14]

Complete Question

 The complete question is shown on the first uploaded image  

Answer:

The total pressure is  P_T  = 10.79*10^{5} N/m^2

The temperature at the bottom is T_b  = 284.2 \ K

Explanation:

From the question we are told that

    The length of the glass tube is  L  = 1.50 \ m

      The length of water  rise at the bottom of the lake  d = 1.33 \ m

     The depth of the lake is  h =  100 \ m

     The air temperature is T_a   =  27 ^oC =  27 +273 =  300 \ K

      The atmospheric pressure is  P_a = 1.01 *10^{5} N/m

      The density of water is \rho =  998 \ kg/m^3

The total pressure at the bottom of the lake is mathematically represented as

                 P_T  =  P_a + \rho g h

substituting values

               P_T  = 1.01*10^{5}  + 998 * 9.8 * 100

               P_T  = 10.79*10^{5} N/m^2

According to ideal gas law

         At the surface the glass tube not covered by water at surface

             P_a V_a =  nRT_a

Where is the volume of

             P_a *A * L  = nRT_a

 At the bottom of the lake  

           P_T V_b  =  nRT_b

Where V_b is the volume of the glass tube not covered by water at bottom

          and  T_b i the temperature at the bottom

  So the ratio between the temperature  at the surface to the temperature at the bottom is mathematically represented as

             \frac{T_b}{T_a}  =  \frac{d * P_T}{P_a * h}

substituting values

           \frac{T_b}{27}  =  \frac{0.133  * 10.79 *10^5}{1.01 *10^{5} * 1.5}

   =>     T_b  = 284.2 \ K

           

       

3 0
3 years ago
He starter motor of a car engine draws a current of 170 AA from the battery. The copper wire to the motor is 6.00 mmmm in diamet
sweet-ann [11.9K]

Answer:

129.2 C

0.33758239177 mm

Explanation:

n = Number density = 8.46\times 10^{28}\ electrons/m^3

i = Current = 170 A

t = Time taken = 0.76 s

d = Diameter = 6 mm

Charge is given by

q=it\\\Rightarrow q=170\times 0.76\\\Rightarrow q=129.2\ C

The charge passing throught the motor is 129.2 C

Current density

J=\dfrac{i}{A}\\\Rightarrow J=\dfrac{170}{\dfrac{\pi}{4}\times (6\times 10^{-3})^2}\\\Rightarrow J=6012520.07236\ A/m^2

Drift velocity is given by

v_d=\dfrac{J}{ne}\\\Rightarrow v_d=\dfrac{6012520.07236}{8.46\times 10^{28}\times 1.6\times 10^{-19}}\\\Rightarrow v_d=0.000444187357592\ m/s

Distance traveled

s=v_dt\\\Rightarrow s=0.000444187357592\times 0.76\\\Rightarrow s=0.00033758239177\ m=0.33758239177\ mm

The electron traveled 0.33758239177 mm

8 0
3 years ago
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