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3 years ago

1. The surface considered for Gauss’s law is called

Physics

2 answers:

lidiya [134]3 years ago

5 0

Answer:

C) Gaussian surface

Explanation:

geniusboy [140]3 years ago

4 0

Answer:

Explanation:

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A car rolls backward from -2 to -10 m/s in 4 seconds. what is the acceleration. PLEASE HELP WILL GIVE BRAINLIEST

pashok25 [27]

$\bf \underline{Given : }$

Initial velocity,u = -2 m/s

Final velocity,v = -10 m/s

Time taken, t = 4 seconds

$\bf \underline{To \: find \: out : }$

Find the acceleration ( a ) .

$\bf \underline{Solution : }$

We know that,

$\sf \: Acceleration = \dfrac{v - u}{t}$

Substituting the values in the above formula, we get

$\implies \sf \: Acceleration = \dfrac{ - 10 - ( - 2)}{4}$

$\implies\sf \: Acceleration = \dfrac{ - 10 + 2}{4}$

$\implies \sf \: Acceleration = \cancel \dfrac{ - 8}{4}$

$\implies\sf \: Acceleration = - 2 \: ms {}^{ - 2}$

Hence,the acceleration of a body is -2 m/s².

5 0

4 years ago

Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th

lozanna [386]

Answer:

Part a)

Velocity of sled

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

Velocity of sled

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

$0 = m_1(v - s) + (m_2 + M)v$

$v = \frac{m_1 s}{m_1 + m_2 + M}$

so velocity of the sled + other person is

$v = \frac{m_1 s}{m_1 + m_2 + M}$

velocity of first man who jump off

$v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s$

$v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}$

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f$

$(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f$

Now we have

$v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s$

Also the speed of second person is given as

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s$

$v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}$

Part c)

change in kinetic energy of sled + two people is given as

$KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2$

here we know all values of speed as we found it in part a) and part b)

4 0

3 years ago

You're using a wedge to split a log. you are hitting the wedge with a large hammer to drive it into the log. it takes a force of

KIM [24]

The work performed on an object is the force multiplied by the distance it is moved, provided the movement is parallel to the force. Since that is the case here, we can get the work by W=Fd=1900N x 0.23m = 437J. This energy is used to split the wood.

6 0

4 years ago

Read 2 more answers

What is the speed of a cheetah that travels 150.0 meters in 6.0 seconds?

HACTEHA [7]

25 meters per second.

To find this, divided 150 by 6 in order to get the correct calculation.

Hope this helps!

4 0

3 years ago

Read 2 more answers

What does not affect the gravitational potential energy of an object

natta225 [31]

Anything really like velocity? as long as its not mass, gravity, and height

Ep = mgh

Those are the only variables that affect potential energy