Answer:
Anaphase
Explanation:
<em>The centromere splits during the anaphase of the cell division. Thus, allowing the two linked chromatids to separate.</em>
A typical chromosome is made up of two sister chromatids joined together by a structure known as the centromere. During cell division - at the metaphase stage - the chromosomes align at the equator of the cell, forming the metaphase plate. The spindle from the opposing ends of the cell engages each chromosome at the kinetochore of the centromere.
<u>At the anaphase stage</u><u>, the centromere splits, leading to the separation of the sister chromatids of each chromosome. The sister chromatids of the same then start migrating in the opposite direction as a result of the shortening of the spindle fiber.</u>
Answer: see the photo attached. (:
Hello!
The atomic number is determined only by the number of protons in the nucleus of an atom. But, in a neutral atom it also represents the number of electrons in the electron cloud.
Neutrons are only important in the nucleus for helping us find atomic weight, which varies as we move along the perodic table and does not always equal the same amount of it's atomic number. Which is why it would not be a suitable answer for the first blank space. Electrons do not work either as they do not exist inside the nucleus but rather outside the atom.
The second space, since it states is in the electron cloud, we can deduct that electrons would be an appropriate answer there.
If you need anymore help feel free to ask, but I hope this answers your question.
Answer:
2 M Al³⁺(aq) and 6 M NO₃⁻(aq)
Explanation:
Al(NO₃)₃ is a strong electrolyte that ionizes according to the following equation.
Al(NO₃)₃(aq) → Al³⁺(aq) + 3 NO₃⁻(aq)
The solution 2.0 M contains 2.0 moles of Al(NO₃)₃ per liter of solution.
The molar ratio of Al(NO₃)₃ to Al³⁺ is 1:1. The concentration of Al³⁺ is:
2.0 mol Al(NO₃)₃/L × (1 mol Al³⁺/1 mol Al(NO₃)₃) = 2.0 mol Al³⁺/L = 2.0 M Al³⁺
The molar ratio of Al(NO₃)₃ to NO₃⁻ is 1:3. The concentration of NO₃⁻ is:
2.0 mol Al(NO₃)₃/L × (3 mol NO₃⁻/1 mol Al(NO₃)₃) = 6.0 mol NO₃⁻/L = 6.0 M NO₃⁻
To solve this you need to find the radius of the bigger cylinder so you have to solve the equation 36π=
π(9). When you solve it you end up with a radius of 2 in which you multiply by 1.2 which gives you the radius of the new cylinder which is 2.4. With the new radius you simply find the volume of the bigger cylinder which is 51.94π
.