Explanation:
The given data is as follows.
= 0.483, ![[Co^{3+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B3%2B%7D%5D)
= 0.173 M,
![[Co^{2+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B2%2B%7D%5D)
= 0.433 M, ![[Cl^{-}]](https://tex.z-dn.net/?f=%5BCl%5E%7B-%7D%5D)
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P = 
Also, we know that
Density = 
So, P = MRT
and, M = 
= 
= 
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E = ![E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5BCo%5E%7B2%2B%7D%5D%5E%7B2%7D%5BCl_%7B2%7D%5D%7D%7B%5BCo%5E%7B3%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%7D)
= 
= 
= 
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at 
is 0.4645 V.
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.
So, there are about (9.30 * 10^-3)(160.36)=1.49 grams
Friction. Imagine rubbing your hand against a carpet and how it gets hot even though you are pushing it afar. That is friction.
The type of bond connects the fatty acid will be " an ester bond".
Fatty acids could be joined to each of the three carbons of the glycerol molecule in a fat molecule by an ester bond that passes through into the oxygen atom. Three molecules are emitted during the establishment of the ester bond. Fats were also known as triacylglycerols as well as triglycerides because they are made consisting of three fatty acids and glycerol.
The three major nutrients in a diet may be carbohydrates, proteins, and fats. According to how many hydrogen bonds they contain, fats are classified as either saturated as well as unsaturated.
The type of bond connects the fatty acid will be " an ester bond".
Hence, the correct answer will be option (c)
To know more about fatty acid
brainly.com/question/13528495
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