Answer:
Concentration of KOH is 0.02M
15.0 mL of a 1.0 M HCl(aq) solution is a better conductor of electricity because it is more concentrated and has greater ions in solution.
Explanation:
Equation of the reaction;
KOH(aq) + HCl(aq) ----> KCl(aq) + H2O(l)
To determine the concentration of the KOH
Concentration of acid CA= 0.010 M
Volume of acid VA= 15.0 ml
Concentration of base CB= ???
Volume of base VB= 7.5 ml
Number of moles of acid NA= 1
Number of moles of base NB= 1
From;
CAVA/CBVB= NA/NB
CAVANB = CBVBNA
CB= CAVANB/VBNA
Substituting values;
CB= 0.010 × 15.0 ×1 / 7.5 ×1
CB= 0.02 M
Therefore, the concentration of the KOH is 0.02M
15.0mL of 1.0 M HCl(aq) is a better conductor of electricity than 15.0mL of 0.010 M HCl(aq) because 15.0mL of 1.0 M HCl(aq) is more concentrated and has more ions in solution than 15.0mL of 0.010 M. Since ions are charge carriers in solution, the more the concentration of ions in solutions, the greater the conductivity of the solution. Hence the answer.
