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V125BC [204]
3 years ago
11

Which of the following is the most likeley example of an favorable mutation

Chemistry
1 answer:
Lana71 [14]3 years ago
8 0
A mutation that gives a rabbit a third ear
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Which of the following statements is not accurate? A. At constant temperature, halving the number of gas particles in a given sp
vlabodo [156]
I suggest you to go with C !! it is absolutely wrong sentence !!

increasing the gas particles will increase the collision between them so !!

your answer is C !!
4 0
4 years ago
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What did the experiments of scientists after John Dalton reveal about his
EastWind [94]

A. Dalton's theory that atoms could not be divided was incorrect

3 0
3 years ago
What element has 42 neutrons
salantis [7]

Answer:

arsenic

Explanation:

4 0
3 years ago
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What atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trif
Nataly_w [17]

Atomic or hybrid orbital on the central br atom makes up the sigma bond between this br and an outer f atom in bromine trifluoride, brf3 is sp2 hybridization

Trigonal hybridization is another name for sp2 hybridization. It entails combining one's' orbital with two 'p' orbitals of equal energy to create a new hybrid orbital known as sp2. A trigonal symmetry combination of s and p orbitals that is kept at 120

One of the hybrid orbitals formed when one s orbital and two p orbitals are mathematically merged to form three new equivalent orbitals orientated toward the corners of a triangle is sp2 hybridization.

The only feasible molecule geometry for sp2 hybridized center atoms is trigonal planar. When all of the bonds are in place, the shape is trigonal planar as well.

To learn more about sp2 hybridization please visit -
brainly.com/question/6270186
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4 0
2 years ago
When 0.514 g of biphenyl (c12h10) undergoes comubustion in a bomb calorimeter, the temperature increases from 25.80 °c to 29.40
slava [35]
The  change  in  internal   energy  of the   combustion  of  biphenyl  in  Kj  is  calculated  as follows

  =heat  capacity of  bomb  calorimeter x  delta  T  where  delta T   is  change   in temperature
delta T  = 29.4  -25.8= 3.6 c

= 5.86 kj/c   x  3.6 c =  21.096  kj


7 0
4 years ago
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