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V125BC [204]
3 years ago
11

Which of the following is the most likeley example of an favorable mutation

Chemistry
1 answer:
Lana71 [14]3 years ago
8 0
A mutation that gives a rabbit a third ear
You might be interested in
Cyclohexane, a commonly used organic solvent, is 85.6% c and 14.4% h by mass with a molar mass of 84.2 g/mol. what is its molecu
puteri [66]

The molecular  formula of   organic solvent  is    <em>C6H12</em>


<h2>calculation</h2><h3>find the empirical formula first as in step 1 and 2</h3>

Step 1: f<em>ind the moles of C and H</em>

  • moles =  % composition/molar mass
  •       from periodic table molar mass of C= 12 g/mol while that of H= 1 g/mol
  • moles is  C is therefore = 85.6/12=  7. 13 moles
  •  moles of H=  14.4/1 - 14.4 moles

  Step 2:  <em>calculate the mole  fraction  by dividing each mole by smallest number of mole(7.13)</em>

  • that is C= 7.13/7.13 = 1

         H=  14.4/7.13 =2

the empirical formula is therefore = CH2

<h2>Then calculate the molecular formula from empirical formula</h2>

step 3: divide the  grams molar mass  by empirical formula mass

               empirical formula mass =  12+(1 x2) = 14 g/mol

    = 84.2/ 14 = 6

step 4: multiply  each of the subscript  within the empirical  formula with the value gotten in step 3

  • that is  [CH2]6 = C6H12  therefore the molecular formula = <u>C6H12</u>
8 0
3 years ago
12) A 17.92 g sample of copper was submerged in water, and the volume reading rose by 2.00 mL. What is the density of the copper
emmasim [6.3K]

Hey there!:

Mass = 17.92 g

Volume = 2.00 mL

Density =  ??

Therefore:

D = m / V

D = 17.92 / 2.00

D = 8.96 g/mL

Hope this helps!

3 0
3 years ago
a diatomic element has six bonding electrons, six non-bonding electrons, and 2 anti-bonding electrons. what is the bond order? g
Deffense [45]

The bond order of a diatomic element with  six bonding electrons, six non-bonding electrons, and 2 anti-bonding electrons is 2 whose formula is( bonding electrons-anti bonding electrons)/2.

<h3>What is an element?</h3>

An element  is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

Learn more about element,here:

brainly.com/question/14347616

#SPJ2

7 0
1 year ago
Read 2 more answers
Consider the titration of 1L of 0.36 M NH3 (Kb=1.8x10−5) with 0.74 M HCl. What is the pH at the equivalence point of the titrati
worty [1.4K]

Answer:

C

Explanation:

The question asks to calculate the pH at equivalence point of the titration between ammonia and hydrochloric acid

Firstly, we write the equation of reaction between ammonia and hydrochloric acid.

NH3(aq)+HCl(aq)→NH4Cl(aq)

Ionically:

HCl + NH3 ---> NH4  +  Cl-

Firstly, we calculate the number of moles of  the ammonia  as follows:

from c = n/v and thus, n = cv = 0.36 × 1 = 0.36 moles

At the equivalence point, there is equal number of moles of ammonia and HCl.

Hence, volume of HCl = number of moles/molarity of HCl = 0.36/0.74 = 0.486L

Hence, the total volume of solution will be 1 + 0.486 = 1.486L

Now, we calculate the concentration of the ammonium ions = 0.36/1.486 = 0.242M

An ICE TABLE IS USED TO FIND THE CONCENTRATION OF THE HYDROXONIUM ION(H3O+). ICE STANDS FOR INITIAL, CHANGE AND EQUILIBRIUM.

                 NH4+      H2O     ⇄  NH3        H3O+

I                0.242                           0             0

C                 -X                              +x              +X

E             0.242-X                          X              X

Since the question provides us with the base dissociation constant value K b, we can calculate the acid dissociation constant value Ka

To find this, we use the mathematical equation below

K a ⋅ K b    = K w

 

, where  K w- the self-ionization constant of water, equal to  

10 ^-14  at room temperature

This means that you have

K a = K w.K b   = 10 ^− 14 /1.8 * 10^-5 =  5.56 * 10^-10

Ka = [NH3][H3O+]/[NH4+]

= x * x/(0.242-x)

Since the value of Ka is small, we can say that 0.242-x ≈  0.242

Hence, K a = x^2/0.242 = 5.56 * 10^-10

x^2 = 0.242 * 5.56 * 10^-10 = 1.35 * 10^-10

x = 0.00001161895

[H3O+] = 0.00001161895

pH = -log[H3O+]

pH = -log[0.00001161895 ] = 4.94

7 0
3 years ago
29 Points!!
atroni [7]
The last one would be false
3 0
3 years ago
Read 2 more answers
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