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3 years ago

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Deuterium (written as d or 2h) is an isotope of hydrogen known as heavy hydrogen. part a balance the given chemical equation usi

ng whole-number coefficients. ?d2(g)+?o2(g)→?d2o(l) enter the coefficients in order separated by commas (e.g., 1,3,2, where 1 indicates the lack of

1 answer:

notsponge [240]3 years ago

7 0

Given unbalanced chemical reaction:

?D₂(g)+ ?O₂(g) →?D₂O(l)

Balancing the given chemical equation using whole-number coefficients:

2D₂(g)+ O₂(g) →2D₂O(l)

Therefore, the coefficients in order separated by commas are:

2, 1, 2

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The lower the ph of a solution, the ______.

gtnhenbr [62]

B

a and c are unrelated
d: ph will increase

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___Al+NaOH=>__Na3AlO3+H2

MaRussiya [10]

Explanation:

<em><u>2Al + 2NaOH + 6H2O → 2Na[Al(OH)4] + 3H2</u></em>

<em><u> $...$ </u></em>

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3 years ago

What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)

pav-90 [236]

Answer:

$pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12$

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3 years ago

Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2

IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at $75^{o}F$ and 14.6 psia.

$\varepsilon$ = 0.00015 ft, Flow rate, (Q) = 48000 $ft^{3}/m$

(a) Formula to calculate hydraulic radius $(r_{H})$ is as follows.

$r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}$

= $\frac{2 \times 1}{2(1) + 2(2)}$

= $\frac{1}{3}$ ft

Formula for equivalent diameter is as follows.

$D_{eq} = 4 \times r_{H}$

= $4 \times \frac{1}{3} ft$

= $\frac{4}{3}$ ft

(b) Formula for velocity floe is as follows.

Q = VA

V = $\frac{Q}{A}$

= $\frac{48000}{2 \times 1}$ ft/min

= 24000 ft/min

(c) Formula to calculate Reynold's number is as follows.

$R_{e}$ = $\frac{D \times V \times \rho}{\mu}$

= $\frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}$ (as $\rho = 0.0744 lb/ft^{3}$ and $\mu$ = 0.0443 lb/ft. hr)

= 53742.66 hr/min

As 1 hr = 10 min. So, $53742.66 hr/min \times \frac{60 min}{1 hr}$

= 3224559.6

(d) Formula to calculate pressure drop $(\Delta P)$ is as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

Putting the given values into the above formula as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

= $\frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}$

= 6.238 $lb/ft^{2}$

5 0

3 years ago

1. Which sample contains a total of 9.0 * 10 ^ 23 atoms ? A) 0.50 mole of HCI B) 0.75 mole of H 2 O C) 1.5 moles of Cu D) 1.5 mo

Alchen [17]

c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.

Explanation:

To convert moles into atoms, the molar amount and number of atom is multiplied by Avagadro's number.

Avagadro's number is 6.022× $10^{23}$

So applying the formula in the given sample:

A) 0.5×6.022× $10^{23}$

3.01× $10^{23}$ atoms.

B) 0.75 mole of H20

O.75×6.022× $10^{23}$

= 4.5166× $10^{23}$ atoms.

C) 1.5 moles of Cu

1.5×6.022× $10^{23}$

= 9.033× $10^{23}$

D). 1.5 moles of H2

1.5 × 2 × 6.022 × $10^{23}$

= 18.066 × $10^{23}$ atoms because H2 is 2 moles of hydrogen.

Atom is the smallest entity of matter having property of the element to which it is a part.

8 0

3 years ago