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MrRissso [65]
3 years ago
7

Deuterium (written as d or 2h) is an isotope of hydrogen known as heavy hydrogen. part a balance the given chemical equation usi

ng whole-number coefficients. ?d2(g)+?o2(g)→?d2o(l) enter the coefficients in order separated by commas (e.g., 1,3,2, where 1 indicates the lack of
Chemistry
1 answer:
notsponge [240]3 years ago
7 0

Given unbalanced chemical reaction:

?D₂(g)+ ?O₂(g) →?D₂O(l)

Balancing the given chemical equation using whole-number coefficients:

2D₂(g)+ O₂(g) →2D₂O(l)

Therefore, the coefficients in order separated by commas are:

2, 1, 2

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Identify areas of Job growth?
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What is oxidized in a galvanic cell with aluminum and gold electrodes ?
k0ka [10]

Answer:

Aluminum metal

Explanation:

In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.

First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:

Al^{3+}+3e^-\rightarrow Al; E^o=-1.66 V

Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.

Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.

Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):Al\rightarrow Al^{3+}+3e^-; E^o=1.66 V\\Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Notice that the overall cell potential upon summing is:

E_{cell}=1.66 V + 1.50 V=3.16 V

Meaning we obey the law of galvanic cells.

Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.

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3 years ago
What is the ph of a 0.034 m hydrochloric acid solution?
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PH= -log [H+]   
= - (log 0.034)   
= - (-1.5)   
= 1.5
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