Which of the following substances would you predict to have the highest ΔHvap?

Chemistry

1 answer:

alexandr402 [8]3 years ago

8 0

Answer: Option (4) is the correct answer.

Explanation:

Heat of vaporization is defined as the heat energy which is necessarily added to a liquid substance in order to transform the quantity of the substance into a gas.

For example, in $H_{2}O$ there will be presence of strong hydrogen bonding and in order to break this bond high amount of heat energy is required.

Whereas $H_{2}$ , $F_{2}$ and $SiF_{4}$ are all covalent compounds which are bonded together by Vander waal forces. As these forces are weak in nature hence, they require less amount of heat energy to convert into vapor state.

Hence, they have low value of $\Delta H_{vap}$ . Also, Ar is a noble gas and it has only Vander waal forces. So, it will also have low value of $\Delta H_{vap}$ .

Therefore, we can conclude that out of the given options $H_{2}O$ have the highest $\Delta H_{vap}$ .

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A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150

Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

$M=\frac{Moles of substance X}{Volume of the solution}$

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

$11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}$

Then you can solve for the volume of the solution:

$Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL$

Hope it helps!

3 0

3 years ago

Sodium Chloride is an ionic compound. Its molar mass is 58.44g. One formula unit of NaCl consists of one____, whose chemical sym

saul85 [17]

Answer: One formula unit of NaCl consists of one cation, whose chemical symbol is $Na^+$ and one anion whose chemical symbol is $Cl^-$

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cation is formed by the metal sodium which forms $Na^+$ and the anion is formed by non metal chlorine which forms $Cl^-$ .

For a formula unit of sodium chloride, the charges have to be balanced , thus the valencies of ions are exchanged and the neutral compound result. Thus

$Na^+$ and $Cl^-$ combine to form neutral $NaCl$