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djyliett [7]
3 years ago
14

Imagine this scenario. All of the trees and plants are removed from a steep mountainside how would the removal of the trees and

plants affect the soil on the mountainside
Chemistry
2 answers:
lilavasa [31]3 years ago
8 0
Nothing unless it was dug out from roots if not they would grom back in a long period of time
aniked [119]3 years ago
6 0

Answer:

Landslides will occur due to the removal of vegetation

Explanation:

<u>Due to the removal of plants and trees from the slope of the mountain, the soil becomes dry and loses its fertility. This dry soil becomes unstable and when it comes in contact with the water (from precipitation), it causes landslides and the materials are eroded along the slope of the valley</u>. When there is vegetation in the slope it absorbs the water into their roots thereby making the slope stable. So vegetations also is an important factor in controlling slope stability.

<u>The landslide refers to the downward motion of particles including rocks, soils, and debris. It occurs when the shear stress exceeds the shear strength of the material</u>.

So a slope that lacks in the vegetation cover is more likely to experience landslide.

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Round off the measurement to three significant figures 12.17º C
prohojiy [21]
12.2 C
It has 3 significant figures now.
6 0
3 years ago
4 HF(g)+SiO2(s) → SiF4(9)+2 H2O(9) <br> Is the Si oxidized or reduced?
Airida [17]

Answer:

Si is reduced since it loses the oxygen atom

8 0
3 years ago
1. The two qualities used to describe winds are________ and speed. 2. a local wing that blows during the day from an ocean towar
Mazyrski [523]
<span>1. The two qualities used to describe winds are direction and speed.
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4 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
What is the first step of a ladybug during the growth and development process​
Sunny_sXe [5.5K]

Answer:

Damian here! (ノ◕ヮ◕)ノ*:・゚✧

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Explanation:

hope this helps? :))

7 0
3 years ago
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