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Verizon [17]
3 years ago
8

Describe the role of the ocean in the water cycle?

Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
First of all, going off of the water cycle: evaporation, condensation, precipitation and collection
What would make the most sense that the ocean would have a role of? Well it would be evaporation in the water cycle because the ocean is 97.5% of all water and is the main source for condensation, precipitation and collection. But it’s main role is collection of water to be evaporated into the cycle.

Hope this helps :)
Ne4ueva [31]3 years ago
5 0

Answer:

Don't get me wrong the seas are, by distant, the biggest store of water on soil, over 96% of all of Earth's water exists within the seas. Not as it were do the seas give dissipated water to the water cycle, they moreover permit water to move all around the globe as sea streams. I mean, that's all i know man, give me a break.

Explanation:

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Explanation:

What occurred then is as a result of nuclear fission. This occurs as the Uranium-235 split into two smaller nuclei while releasing high energy neutrons. These neutrons bombard existing U-235 in the atmosphere and this reaction continue in a spontaneous manner until a chain reaction is formed of U-235, whose fall out fills the environment. This process was what led to people been exposed to high intensity radiation in the days and months after the atomic bomb was dropped.

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What is the freezing point of a solution made with 1.31 mol of CHCl3 in 530.0 g of CCl4 (Kf =29.8 degrees C/m, Freezing point of
Allisa [31]

73.606 °C is the freezing point of the solution made with with 1.31 mol of CHCl3 in 530.0 g of CCl4.

Explanation:

Data given:

number of moles of CHCl3 = 1.31 moles

mass of solvent CHCl3 = 530 grams or 0.53 kg

Kf = 29.8 degrees C/m

freezing point of pure solvent or CCl4 =  -22.9 degrees

freezing point = ?

The formula used to calculate the freezing point of the mixture is

ΔT = iKf.m

m=  molality

molality = \frac{moles of solute}{mass of solvent in kilograms}

putting the value in the equation:

molality= \frac{1.31}{0.53}

             = 2.47 M

Putting the values in freezing point equation

ΔT = 1.31 x 29.8 x 2.47

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