You can identify a compound to be an alcohol when it has a hydrocarbon chain and a hydroxyl functional group or -OH group. Also, from the name, you can tell that it is an alcohol is the suffix -ol is present. Examples are ethanol and methanol. Alcohol is any organic substance that contains an hydroxyl group bonded to a carbon atom that is saturated. Alcohols can be classified as primary, secondary or tertiary depending on where the hydroxyl functional group is attached in the hydrocarbon chain. It is a primary alcohol when OH is attached to the first carbon atom. Secondary alcohol, and tertiary alcohols has a general formula CHROH and CR2OH, respectively where R represents a hydrocarbon chain.<span />
Answer:
Following are the explanation to this question:
Explanation:
The salts of carboxylate are named by the writing, which is also named as the creation of the first, which is followed by the name of the carboxylic acid were '-ic' of the acid end and replaced by the 'ate'.
Following are the description of the given reaction:
In reaction A:
2-Bromopropanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Bromopropanate
In reaction B:
2-Methylhexanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Methyl hexanoate
Answer:
Molar mass = 32.64 g / mol.
The density of gas is 1.3 × 10⁻³g/mL.
Explanation:
Given data:
Mass of sample = 2.35 g
Pressure = 1.05 atm
Volume = 1.85 L (1.85 × 1000 = 1850 ml)
Temperature = 55 °C (55+ 273.15 = 328.15 K)
Density = ?
Formula:
d = m/ v
The volume of flask would be the volume of gas.
d = 2.35 g / 1850 mL = 0.0013 g/mL or 1.3 × 10⁻³g/mL
The density of gas is 1.3 × 10⁻³g/mL.
Molar mass:
Now we will calculate the moles of a gas first in order to find the molar mass of a gas.
Formula:
PV =nRT
n = number of moles.
n = PV / RT
n = 1.05 atm × 1.85 L / 0.0821 atm. dm³. K⁻¹ . mol⁻¹ × 328.15 K
n = 1.9425 atm . L / 26.941115 atm . dm.³mol⁻¹
n = 0.072 mol
Now we will find the molar mass.
Number of moles = mass / molar mass
0.072 mol = 2.35 g / molar mass
Molar mass = 2.35 g / 0.072 mol
Molar mass = 32.64 g / mol
Answer:
2.33*10^-15 s
Explanation:
We need to estimate the period of oscillation of an electron that bounced up/down due to the effects of a passing packet of red light. The period of oscillation is the wavelength of the red light divided by the speed of the red light. We know that:
V = f*λ
where V = speed of the red light = 3*10^8 m/s
f = frequency = 1/T where T is the period of oscillation in seconds (s)
λ = the wavelength of the red light = 0.7*10^-6 m
Thus:
V = λ/T
T = λ/V = (0.7*10^-6)/(3*10^8) = 2.33*10^-15 s
<span>The equation that represents the pressure of a gas under ideal conditions is the PV= nRT. The pressure of a gas is the exerted force that has various properties such as the compressibility and the viscosity. Compressibility refers to the response actions when pressure is applied.</span>
