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Fofino [41]
10 months ago
9

When a pulse travels on a taut string, does it always invert upon reflection? Explain.

Physics
1 answer:
sineoko [7]10 months ago
6 0

If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects.

Hence, If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only  it reflects off via a means in which the wave speed is said to be smaller.

<h3>When a wave pulse on a string reflects?</h3>

If a pulse on string is said to show or reflects from free end, the outcome of the resultant pulse is said to be made in such a way that the said slope of string is seen at free end is zero.

Therefore, If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects.  If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only  it reflects off via a means in which the wave speed is said to be smaller.

Learn more about taut string from

brainly.com/question/13740518

#SPJ4

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In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.1
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6,600N

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A 5.6 cm diameter parallel-plate capacitor has a 0.58 mm gap. What is the displacement current in the capacitor if the potential
BARSIC [14]

Answer:

1.88\cdot 10^{-5} A

Explanation:

The capacitance of a parallel plate capacitor is given by:

C=\frac{\epsilon_0 A}{d} (1)

where

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

The charge stored on the capacitor is given by

Q=CV (2)

where C is the capacitance and V is the voltage across the capacitor.

The displacement current in the capacitor is given by

J=\frac{Q}{t} (3)

where t is the time elapsed

Substituting (1) and (2) into (3), we find an expression for the displacement current:

J=\frac{CV}{t}=\frac{\epsilon_0 A}{d} \frac{V}{t}

where we have

A=\pi (\frac{d}{2})^2=\pi (\frac{0.056 m}{2})^2=2.46\cdot 10^{-3} m^2

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Substituting into the equation, we find

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