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11 months ago

When a pulse travels on a taut string, does it always invert upon reflection? Explain.

1 answer:

6 0

If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects.

Hence, If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only it reflects off via a means in which the wave speed is said to be smaller.

<h3>When a wave pulse on a string reflects?</h3>

If a pulse on string is said to show or reflects from free end, the outcome of the resultant pulse is said to be made in such a way that the said slope of string is seen at free end is zero.

Therefore, If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects. If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only it reflects off via a means in which the wave speed is said to be smaller.

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Answer:

option C

Explanation:

The correct answer is option C.

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To overcome the gravitation force on the biker the velocity of the biker should be high such that centripetal acceleration of the biker can overcome the gravity force acting on the biker.

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3 years ago

This is a machine that converts electrical energy into mechanical energy.

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<h2>Answer:</h2>

Motor

<h2>Explanation:</h2>

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3 years ago

Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.

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Answer: A

Explanation: We know that f=p*n

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1 year ago

Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that

elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

E_p = 4.74 *10^(-12) eV

E_k = 490 eV

Explanation:

part a

The potential difference between two plates = 490 V

Distance between two plates = 8.5 cm

Answer: The positive plate is at higher potential because of convention.

part b

Electric Field between the plates

E = V / d

E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

W = V*q

W = 490 * 1.602*10^-19

W = 7.85 * 10^-17 J

or W = 490 eV

Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

Very very small E_p approximately 0

Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

E_k = 490eV - 4.74*10^(-12)eV

E_k = 490 eV

Answer: Kinetic Energy of an electron gained E_k = 490 eV

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