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1 year ago

When a pulse travels on a taut string, does it always invert upon reflection? Explain.

1 answer:

6 0

If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects.

Hence, If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only it reflects off via a means in which the wave speed is said to be smaller.

<h3>When a wave pulse on a string reflects?</h3>

If a pulse on string is said to show or reflects from free end, the outcome of the resultant pulse is said to be made in such a way that the said slope of string is seen at free end is zero.

Therefore, If pulse travels on a taut string, it may or may not invert upon reflection because it is one that tends to depends on the place the wave reflects. If reflecting is obtained from a less dense string, the reflected part of the wave will tend to be from be right side up. A wave inverts if only it reflects off via a means in which the wave speed is said to be smaller.

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marishachu [46]

solution:

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so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

d = 0*4.0 + 1/2*9.8*4.0^2

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3 years ago

If you stood on a planet having a mass four times higher than Earth's mass, and a radius two times 70) lon longer than Earth's r

BigorU [14]

CHECK COMPLETE QUESTION BELOW

you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?

A) four times more than you do on Earth.

B) two times less than you do on Earth.

C) the same as you do on Earth

D) two times more than you do on Earth

Answer:

OPTION C is correct

The same as you do on Earth

Explanation :

According to law of gravitation :

F=GMm/R^2......(a)

F= mg.....(b)

M= mass of earth

m = mass of the person

R = radius of the earth

From law of motion

Put equation b into equation a

mg=GMm/R^2

g=GMm/R^2

g=GM/R^2

We know from question a planet having a mass four times that of earth mass and a radius two times of earth radius if we substitute we have

m= 4M

r=(2R)^2=4R^2

g= G4M/4R^2

Then, 4in the denominator will cancel out the numerator we have

g= GM/R^2

Therefore, g remain the same

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3 years ago

A stone dropped from the top of a building reaches the ground with a velocity of 49ms¹. If the acceleration due to gravity is 9.

bezimeni [28]

Explanation:

Given:

v₀ = 0 m/s

v = 49 m/s

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Find: t

v = at + v₀

49 m/s = (9.8 m/s²) t + 0 m/s

t = 5 s

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2 years ago

Bus starts from rest if the acceleration of the bus is 0.5 MS squared what will be the velocity at the end of two minutes and wh

Nutka1998 [239]

Explanation:

Given that,

Initial speed of the bus, u = 0

Acceleration of the bus, a = 0.5 m/s²

Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.

So,

$a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s$

Let d is the distance cover during that time. So,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m$

So, the final speed is 60 m/s and the distance covered during that time is 3600 m.

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3 years ago

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Fudgin [204]

Speed = distance / time
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