The answer choices are

Mathematics

1 answer:

sattari [20]3 years ago

7 0

Answer:

Since they already have 335.80, we add that to what additional more to make their goal.

Since ome candle for 3.65 then for c candles, its 3.65 × c or (3.65c)

335.80 + 3.65c = 803

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At the beginning of 2010, City A had a population of 2,425 and was growing by 27 residents per year. City B had a population of

d1i1m1o1n [39]

Answer: 17 years

Step-by-step explanation:

City A is currently 2,425 people in number and growing at 27 per year.

An expression to find the population in a given year assuming the year is x would be:

= 2,425 + 27 * x

= 2,425 + 27x

Applying the same logic to City B would give an expression of:

= 1,813 + 63x

Equating these together will give the year they will be the same:

2,425 + 27x = 1,813 + 63x

2,425 - 1,813 = 63x - 27x

612 = 36x

x = 612/36

x = 17 years

4 0

3 years ago

Read 2 more answers

Look at the pic plsssssss

Deffense [45]

Answer:

I can't see it

Step-by-step explanation:

you should zoom in a little bit please

5 0

3 years ago

Write the inverse function for the function, ƒ(x) = 1/2x + 4. Then, find the value of ƒ -1(4). Type your answers in the box. ƒ -

katrin2010 [14]

As you know, to get the inverse of any expression, we start off by switching the variables about and then solving for "y",

$\bf \stackrel{f(x)}{y}=\cfrac{1}{2}x+4\qquad \qquad \stackrel{inverse}{\underline{x}=\cfrac{1}{2}\underline{y}+4}\implies x-4=\cfrac{1}{2}y
\\\\\\
2x-8=\stackrel{f^{-1}(x)}{y}
\\\\\\
f^{-1}(4)=2(4)-8\implies f^{-1}(4)=0$

4 0

3 years ago

Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.