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inna [77]
3 years ago
13

Steve bought 2 plain and 1/4 of a pepperoni pizza. In all how much pizza did he buy?

Mathematics
1 answer:
sineoko [7]3 years ago
7 0
In all he brought

Plain pizza + pepperoni pizza

= 2 + ¼
= 2¼
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3 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

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<h2><u>Given</u><u> </u></h2>

Perpendicular = x

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{ \sf{sin \:  \: 45 {}^{ \degree}   = \dfrac{1}{ \sqrt{2}  }  =  \dfrac{x}{ 30} }}

{ \sf{x =  \dfrac{30}{ \sqrt{2} } }}

<h2>∴ x ( Perpendicular)= 15√2 <u>Ans</u><u>.</u></h2>
3 0
3 years ago
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